1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olchik [2.2K]
3 years ago
7

PLEASE HELP ME IM STRUGGLING SO HARD I BEG OF YOU I WILL NAME MY CHILDREN AFTER YOU!!!!!!!

Mathematics
2 answers:
tangare [24]3 years ago
7 0
12u + 12(15) = 756
multiply 12 and 15
12u + 180 = 756
subtract 180 from both sides
12u = 576
divide 12 on both sides
u = 48
Natali5045456 [20]3 years ago
4 0

Answer:

Cost of one uniform = $48

Step-by-step explanation:

Since there are 12 players and each basketball costs $15,

12 × 15 = $180

Now we know the amount for basketballs, we can find the total cost of uniforms,

$756 - $180 = $576

Cost of uniform per person,

576/12 = $48

You might be interested in
What is the length of ab
Marina86 [1]

Answer:

a,2

Step-by-step explanation:

3×=4×-2

if ×=2

3(2)=4(2)-2

6=8-2

6=6

this is the answer I hope it will help you

8 0
4 years ago
Carl is raising money for his football team. He is selling chocolate bars for $1.50 each and cookies for $2. He sold all 20 of h
stich3 [128]

Answer:

Carl has to sell at least 8 cookies.

c\geq 7.5

Step-by-step explanation:

Carl gets \$1.50 by selling 1 chocolate bar.

Earning from chocolate bars:

Total\ chocolate\ bar=20\\\\Earning\ from\ one\ chocolate\ bar=\$1.50\\\\Total\ earning\ from\ chocolate\ bar=Total\ chocolate\ bar\times cost\ of\ 1\ chocolate\ bar=20\times 1.5=\$30

Earning From cookies:

Let\ total\ number\ of\ cookies=c\\\\Cost\ of\ 1\ cookie=\$2\\\\Earning\ from\ cookies=2\times c=2c

Total\ earning=Earning\ from\ cookies+Earning\ from\ cookies+Earning\ from\ chocolate\ bars\\\\Total\ earning=30+2c

Carl wants to raise at least \$55

Total\ earning\geq 55\\\\2c+30\geq 55\\\\2c\geq 55-30\\\\2c\geq 15\\\\c\geq7.5

7 0
3 years ago
1 – 7k + 3k 2 + 10k + 7 – 5k 2
Katyanochek1 [597]

1) The variables are "k"

2) There are 4 terms

3) The coefficients are k

4) The constants are -7, 3, 10, -5

5) The like terms is -7k, 3k, 10k, -5k

The answers are pretty direct but, hope this answers your question.

Have a great day/night!

8 0
3 years ago
Read 2 more answers
If the retail price of an item is 70$ and its markuped by35%, what is its wholesale price?
sveta [45]

Answer:

94.50$

Step-by-step explanation:

4 0
3 years ago
Find the mean absolute<br> deviation of the set of data.<br> 4, 5, 8, 8, 10 (I also need on this)
Klio2033 [76]

Answer:

MAD = 0

Step-by-step explanation:

When I calculated this by hand I got 0. To find the MAD:

1. You first need to find the mean of the numbers.

4 + 5 + 8 + 8 + 10 = 35

35/5 = 7

the mean value = 7

2. Then you must find the absolute value of the difference between each data value and the mean: |data value – mean|

(4 - 7) = -3

(5 - 7) = -2

(8 - 7) = 1

(8 - 7) = 1

(10 - 7) = 3

3. Add the difference values up

(-3) + (-2) + 1 + 1 +3 = 0

4. Divide the sum of the absolute values of the differences by the number of data values.

0/5 = 0

3 0
4 years ago
Other questions:
  • I need help.What do I do?
    13·2 answers
  • Find the domain of the function using interval notation ​
    12·1 answer
  • Find two positive numbers whose ratio is 2:3 and whose product is 600.
    12·1 answer
  • What are the common multiples of 8,10,12?
    8·2 answers
  • For the equation --4y = 8x, what is the constant of variation?
    15·1 answer
  • 144 out of 600 students took Business Mathematics. What percent of students did not take the course?
    9·2 answers
  • А
    9·1 answer
  • The perimeter of a rectangle with a width x and a length that is 3 times the width
    13·1 answer
  • Please answer and thank you very much if u do
    11·2 answers
  • No links Lean's mother paid 2.16 for 3 pounds of sugar. How much would 1 pound of sugar cost???
    13·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!