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V125BC [204]
3 years ago
6

Number 65 is what I need please

Mathematics
1 answer:
Inessa05 [86]3 years ago
7 0
8 Summers’s what she will need
You might be interested in
3) Find the value of FD. bited F 12 12 13x - 16 E 4x+11 D​
vlada-n [284]

The Length of FD = 26 cm

According to the given information

FE = FC = 12cm

As FE, FC both are radius of circle

The tangent segments to a circle from a external point are equal

Hence

CD = ED

13x - 16 = 4x + 11

13x - 4x = 11 + 16

9x = 27

x = 27/9

x = 3

CD = 13x - 16

     = 13 × 3 - 16

     = 23 cm

ED = 4x + 11

     = 4 × 3 + 11

     = 23 cm

In Triangle FED

FE is perpendicular to ED

According to Pythagoras Theorem

FD^{2}= FE^{2}+ED^{2}

       = 12^{2}+ 23^{2}

       = 673

FD = 26 cm approx.

The Length of FD = 26 cm

To know more about Pythagoras Theorem

brainly.com/question/343682

#SPJ1

8 0
1 year ago
115>5.75x+28.75 what is x
julsineya [31]
115>5.75x+28.75
5.75x+28.75<115
5.75x<115-28.75
5.75x<86.25
x<86.25/5.75
x<15       or (-∞,15)

Answer: x<15      or        (-∞,15)
4 0
3 years ago
How do i calculate this? PV = 100,000(1+0.03)
meriva

Answer:

  103,000

Step-by-step explanation:

Use your knowledge of decimal arithmetic. Or, use a calculator.

  100,000(1 +.03) = 100,000·1.03 = 1000·103 = 103,000

5 0
3 years ago
Winter math packet
stealth61 [152]

Answer:

32. C

34.C

36. 2

8 0
2 years ago
Read 2 more answers
David goes into a candy store with $5.00. He buys 9 peppermints for $0.15 each and some sour candies. Each sour candy costs $0.2
Agata [3.3K]

Answer:

5 ≥ 9*.15 + x*.25

He can buy up to 14 candies

Step-by-step explanation:

Total money ≥number of peppermints * cost per peppermint + number of sour candies * cost per sour candy

We know he has 5 dollars.  He bought 5 peppermints at $.15 cents each and x sour candies at $.25 each

Substituting in

5 ≥ 9*.15 + x*.25

5≥1.35 + .25x

Subtract 1.35 on each side

5-1.35 ≥ 1.35-1.35+.25x

3.65≥.25x

Divide by .25 on each side

3.65/.25 ≥ .25x/.25

14.6 ≥ x

He can buy up to 14 candies.  You can't buy part of a candy

6 0
3 years ago
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