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Zanzabum
2 years ago
12

Air pressure is measured in pascals. For a professional American football game, the ball should be inflated to about 90,000 pasc

als. Scientists studied the effects of air temperature on the pressure inside American footballs by taking these steps:
1. Prepare 100 footballs.
2. Measure each football's air pressure.
3. Divide footballs into 10 groups.
4. Place the groups in different lockers cooled to different air temperatures.
5. After 12 hours, remove the footballs from lockers.
6. Measure each football’s pressure again.
7. Compare the new pressures to the starting pressures.

What two terms best describe the variable "air pressure inside the football" in this experiment?

independent, qualitative
independent, quantitative
dependent, qualitative
dependent, quantitative
Chemistry
1 answer:
Tatiana [17]2 years ago
7 0

The variable "air pressure inside the football" in this experiment is quantitative and dependent variable. Hence, option D is correct.

<h3>What is the dependent variable?</h3>

The dependent variable is the variable that is being measured or tested in an experiment.

In the experiment, the scientist filled the footballs with fix quantity of pressure which was then kept for 12 hours. After 12 hours the pressure inside the footballs was again measured. Pressure here is a quantitative variable.

Since the air temperature is an independent variable. The pressure being the dependent variable depends upon the temperature of the air.

Independent variable; The variable which does not depends upon any other variable.

Dependent variable; The variable which depends upon the independent variable or varies with the change independent variable.

Qualitative variables are variables which cannot be expressed in form of numbers. They generally convey the characteristic, category, quality or type.

Whereas Quantitative variables are the variables which can be expressed in the form of numbers. These are the variables which exist along the continuous sequence.

Learn more about dependent variables here:

brainly.com/question/1479694

#SPJ1

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Draw the product formed when cyclohexene is reacted with H2 in the presence of Pt. Note: If adding hydrogen atoms to a carbon at
tigry1 [53]

Answer:

It has been drawn and uploaded as an attachment. Please download it to see the structure.

Explanation:

The product formed as a result of the reaction of cyclohexene with H2​ in presence of Pt (platinum) can be described as catalytic hydrogenation. Catalytic hydrogenation is defined as the process of hydrogen addition in the presence of a catalyst, which in this case is platinum.

Note that Cyclohexene (alkene) is a hydrocarbon molecule represented by the chemical formula, C6​H10​ .

It consists of a double bond. During the hydrogenation reaction, the alkene undergoes an addition reaction to give alkane which is a saturated hydrocarbon as the product.

The first step in order to derive the product is to draw the chemical structure of cyclohexene and identify the double bond present in it.

The final product can be derived by replacing the double bond with the single bond and satisfying all the valences of the carbon atom. The final product structure has been drawn and uploaded as an attachment. Please download it to see the structure.

Ans:

The structure of the cyclohexane thus, formed has been shown as follows with all the hydrogen atoms:

3 0
3 years ago
What is the mass (grams) of salt in 10.0 m' of ocean water? ball park-4x10's (1.000 molsalt -58.44 g salt, 1.0 L ocean water -0.
koban [17]

Answer:

3.5 × 10⁵ g of salt

Explanation:

<em>What is the mass (grams) of salt in 10.0 m³ of ocean water?</em>

We have this data:

  • 1.000 mol salt is equal to 58.44 g salt
  • 1.0 L of ocean water contains 0.60 mol of salt

We will need the following relations:

  • 1 L = 1dm³
  • 1 m³ = 10³ dm³

We can use proportions:

10.0m^{3} .\frac{10^{3}dm^{3}  }{1m^{3} } .\frac{1L}{1dm^{3} } .\frac{0.60molSalt}{1.0L} .\frac{58.44gSalt}{1molSalt} =3.5 \times 10^{5} gSalt

8 0
3 years ago
If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density
ankoles [38]

Answer:

The length of the wire = 352.66 feet.

Explanation:

A copper refinery produces a copper ingot weighing 150 lb. If the copper is drawn into wire whose diameter is 9.50 mm, how many feet of copper can be obtained from the ingot? The density of copper is 8.94 g/cm3. (Assume that the wire is a cylinder whose volume is V = πr2h, where r is the radius and h is its height or length.)

Step 1: Convert lb to kg

150 lb = 68.0389 kg

Step 2: Calculate volume of copper

Volume = mass / density

Volume = 68038.9 grams / 8.94 g/cm³

Volume = 7610.6 cm³ Cu

Step 3: Calculate length of wire

The diameter of the wire is 9.50 mm, so the radius is half of that (4.75 mm), or 0.475 cm.

The total "volume" of the wire is πr²h = (π)*(0.475 cm)²(h) = 0.708h = 7610 cm^3

7610 = 0.708h

h = 10749 cm = length of wire

The length of the wire = 352.66 feet.

7 0
3 years ago
How much force is needed to accelerate a 66 kg skier at 2 m/sec2
alexgriva [62]

Answer:

132N

Explanation:

F=ma

F=66×2

F=132N

7 0
3 years ago
What is the formula of a compound in which element y form ccp lattice and atom x occupy 1/3rd of tetrahedral voids
Kisachek [45]
Y : CCP : 4 atoms
X : tetrahedral voids would be 1/3 × 8 = 8/3

so formula would be Y12X8 or Y3X2 !!
5 0
3 years ago
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