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Natalija [7]
3 years ago
9

Which procedure would best allow a scientist to observe a chemical property of hydrochloric acid (HCI) solution?

Chemistry
2 answers:
makkiz [27]3 years ago
6 0
Effervescence of h2 gas will be produced which burns off a glowing split with a pop sound when hcl reacts with a base
ss7ja [257]3 years ago
4 0

Answer:

Adding a piece of Zn

Explanation:

Adding zinc (Zn) to a hydrochloric (HCl) solution will prove its acidity with a redox reaction:

Zn(s) + 2H^+(aq) \longrightarrow Zn^{+2}(aq) + H_2(g)

This reaction can be confirmed,  by the observation of little bubbles in the surface of the metal: that bubbles are the hydrogen gas generated.

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how many moles of sodium hydroxide (NaOH) are required to completely neutralize 2 mol of nitric acid (HNO3)
Brut [27]

2 moles of sodium hydroxide will be needed.

<h3><u>Explanation</u>:</h3>

Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.

The reaction between them are

NaOH +HNO3 =NaNO3 +H2O.

So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.

6 0
3 years ago
If the particles of matter that make up a substance are relatively far apart and can move freely, the substance is in what state
Novay_Z [31]

Answer:

Gaseous

Explanation:

Gasses can move freely and do not form the shape of their containers

Liquids are more free than solids, but they conform to the shape of their container

Solids are not free

5 0
3 years ago
What mass of calcium carbonate is produced when 250 mL of 6.0 M sodium carbonate is added to 750 mL of 1.0 M calcium fluoride
Savatey [412]

<u>Given:</u>

Volume of Na2CO3 = 250 ml = 0.250 L

Molarity of Na2CO3 = 6.0 M

Volume of CaF2 = 750 ml = 0.750 L

Molarity of CaF2 = 1.0 M

<u>To determine:</u>

The mass of CaCO3 produced

<u>Explanation:</u>

Na2CO3 + CaF2 → CaCO3 + 2NaF

Based on the reaction stoichiometry:

1 mole of Na2CO3 reacts with 1 moles of Caf2 to produce 1 mole of caco3

Moles of Na2CO3 present = V * M = 0.250 L * 6.0 moles/L = 1.5 moles

Moles of CaF2 present = V* M = 0.750 * 1 = 0.750 moles

CaF2 is the limiting reagent

Thus, # moles of CaCO3 produced = 0.750 moles

Molar mass of CaCO3 = 100 g/mol

Mass of CaCO3 produced = 0.750 moles * 100 g/mol  = 75 g

Ans: Mass of CaCO3 produced = 75 g

7 0
3 years ago
What is produced when an acid and an alkali react?
marta [7]
The answer is D: Salt and Water
6 0
2 years ago
Read 2 more answers
Slove this fill in blanks​
bagirrra123 [75]

Answer:

1) Heterogeneous mixture

2). homogeneous mixture

3) water is solvent and sugar is solute

4). sublimation process

3 0
2 years ago
Read 2 more answers
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