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Natalija [7]
3 years ago
9

Which procedure would best allow a scientist to observe a chemical property of hydrochloric acid (HCI) solution?

Chemistry
2 answers:
makkiz [27]3 years ago
6 0
Effervescence of h2 gas will be produced which burns off a glowing split with a pop sound when hcl reacts with a base
ss7ja [257]3 years ago
4 0

Answer:

Adding a piece of Zn

Explanation:

Adding zinc (Zn) to a hydrochloric (HCl) solution will prove its acidity with a redox reaction:

Zn(s) + 2H^+(aq) \longrightarrow Zn^{+2}(aq) + H_2(g)

This reaction can be confirmed,  by the observation of little bubbles in the surface of the metal: that bubbles are the hydrogen gas generated.

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Class material don't interact please
bagirrra123 [75]

A 0.00143 M  concentration of MnO4^- is not a reasonable solution .

<h3>Number of moles of carbonate</h3>

The ions left in solution are Na^+ and NO3^-

Number of moles of calcium nitrate  = 100/1000 L × 1 = 0.1 moles

Since;

1 mole of sodium carbonate reacts with 1 mole of calcium nitrate  then 0.1 moles of sodium carbonate were used.

<h3>Conductivity of filtrate</h3>

The claim of the student that the concentration of sodium carbonate is too low is wrong because the value was calculated from concentration  and volume of calcium nitrate  and not using the precipitate. If the filtrate is tested for conductivity, it will be found to conduct electricity because it contains sodium and NO3 ions.

2) In the reaction as shown, the MnO4^- ion was reduced.

The initial volume is 3.4 mL while the final volume is 29.6 mL.

Number of moles of MnO4^- ion = (29.6 mL - 3.4 mL)/1000 × 0.0235 M = 0.0006157 moles

<h3>The calculations are performed as follows</h3>

  • If 2 moles of MnO4^- reacted with 5 moles of acid

0.0006157 moles of MnO4^- reacted with  0.0006157 moles ×  5 moles/ 2 moles

= 0.0015 moles

  • In this case, number of moles of acid = 0.139 g/90 g/mol = 0.0015 moles

Number of moles of MnO4^-  = 0.00143 M × (29.6 mL - 3.4 mL)/1000

= 0.000037 moles

  • If 2 moles of MnO4^- reacts with 5 moles of acid

0.000037 moles of MnO4^- reacts with 0.000037 moles × 5 moles/ 2 moles

= 0.000093 moles

  • Hence, this is not a reasonable amount of solution.

Learn more about MnO4^- : brainly.com/question/10887629

8 0
2 years ago
Can someone answer that first this pls im lost
Alchen [17]
-Just look up “H2O lewis structure
-1.5
-Don’t know the VSEPR
-Polar Covalent
-Again, don’t know VSEPR
-Just look up H2O molecule
4 0
2 years ago
Which of the following is true about subatomic particles?
galben [10]

Answer:

d

Explanation:

neutrons and protons have the mass nearly 1.67*10-24 g

but neutrons have no charge.. protons are positively charged

6 0
2 years ago
Convert 0.02 g/mL to the unit g/L.
Vilka [71]
0,02 g/mL = 20 g/L

:)
4 0
3 years ago
Which is the correct net ionic equation for the following reaction: H3PO4 (aq) + 3 LiOH (aq) &gt; Li3PO4 (aq) + 3 H2O (l)?
torisob [31]

Answer: The correct option for the chemical equation H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l) is 1.

The correct option for the chemical equation 2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l) is 3.

Explanation:

  • For the chemical equation:

H_3PO_4(aq.)+3LiOH(aq.)\rightarrow Li_3PO_4(aq.)+3H_2O(l)

H_3PO_4 is a weak acid and hence will not dissociate into ions whereas LiOH is a strong base and will easily dissociate into ions.

The product Li_3PO_4 is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

H_3PO_4(aq.)+3Li^{3+}(aq.)+3OH^-(aq.)\rightarrow 3Li^{3+}(aq.)+PO_4^{3-}(aq.)+3H_2O(l)

Net ionic equation becomes:

H_3PO_4(aq.)+3OH^-(aq.)\rightarrow PO_4^{3-}(aq.)+3H_2O(l)

So, the correct option is 1.

  • For the chemical equation:

2HBr(aq.)+Co(OH)_2(aq.)\rightarrow CoBr_2(aq.)+2H_2O(l)

HBr and Co(OH)_2 are strong acid and strong base respectively, hence they will easily dissociate into ions.

The product, CoBr_2 is is soluble in water and hence, will dissociate into its respective ions. Hence, the ionic equation for this reaction is:

2H^+(aq.)+2Br^-(aq.)+Co^{2+}(aq.)+2OH^-(aq.)\rightarrow Co^{2+}(aq.)+2Br^-(aq.)+H_2O(l)

The net ionic equation becomes:

H^+(aq.)+OH^-(aq.)\rightarrow H_2O(l)

So, the correct option is 3.

4 0
2 years ago
Read 2 more answers
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