Frozen. Most of Greenland is covered in freshwater that is frozen.
Answer: The categories of intermolecular forces in the molecules above are dispersion forces, dipole forces, hydrogen bonding.
Explanation:
Here are the different kinds of intermolecular forces present in the above;
Ethane - C2H6 has London dispersion forces—it’s a nonpolar covalent compound— and no other intermolecular attractions.
Dimethyl ether - CH₃OCH₃ has London dispersion force, dipole-dipole attraction, and hydrogen bonding
Ethanot- C2H5OH has has London dispersion force, dipole-dipole attraction, and hydrogen bonding
Answer:
76,6 kg
Explanation:
A kg it's equal to 1x10^3 grams
A Gigagrams it's equal to 1x10^9 grams
Knowing this, a kg it's equal to 1x10^6 gigagrams
![7,66*10^{-5}[gigagram]*\frac{1*10^6 [kg]}{1 [gigagram]}= 76.6 [kg]](https://tex.z-dn.net/?f=7%2C66%2A10%5E%7B-5%7D%5Bgigagram%5D%2A%5Cfrac%7B1%2A10%5E6%20%5Bkg%5D%7D%7B1%20%5Bgigagram%5D%7D%3D%2076.6%20%5Bkg%5D)
Explanation: During winters, there is decrease in temperature which leads to the freezing of water molecules.
The state change occurs from liquid state to solid state.
In case of water, the inter-molecular forces between the molecules decreases which leads to the increase in volume.
Which in turn leads to the decrease in the density of solid (ice). This increase in density tends to the floating of ice on water.
![Density=\frac{Mass}{Volume}](https://tex.z-dn.net/?f=Density%3D%5Cfrac%7BMass%7D%7BVolume%7D)
Thus, on freezing, the water expands and hence, there will be more space for the arctic animals to hunt in winters.
Answer:
About 2.29 M.
Explanation:
Recall that molarity is defined by moles of solute over liters of solution.
Our solute is 105 grams of calcium nitrate (Ca(NO₃)₂)).
Convert 105 grams of Ca(NO₃)₂ to moles. The molecular weight of Ca(NO₃)₂ is 164.10 g/mol:
![\displaystyle 105\text{ g Ca(NO$_3$)$_2$}\cdot \frac{1\text{ mol Ca(NO$_3$)$_2$}}{164.10\text{ g Ca(NO$_3$)$_2$}} = 0.640\text{ mol Ca(NO$_3$)$_2$}}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20105%5Ctext%7B%20g%20Ca%28NO%24_3%24%29%24_2%24%7D%5Ccdot%20%5Cfrac%7B1%5Ctext%7B%20mol%20Ca%28NO%24_3%24%29%24_2%24%7D%7D%7B164.10%5Ctext%7B%20g%20Ca%28NO%24_3%24%29%24_2%24%7D%7D%20%3D%200.640%5Ctext%7B%20mol%20Ca%28NO%24_3%24%29%24_2%24%7D%7D)
Convert 280. grams of water to liters. Recall that the density of water is given by 1.00 g/mL:
![\displaystyle \begin{aligned} D & = \frac{m}{V} \\ \\ V & = \frac{m}{D} \\ \\ & = \frac{(280.\text{ g})}{\left(\dfrac{1.00\text{ g}}{1\text{ mL}}\right)} \\ \\ & = 280. \text{ mL}\cdot \frac{1\text{ L}}{1000\text{ mL}} = 0.280\text{ L soln.}\end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20D%20%26%20%3D%20%5Cfrac%7Bm%7D%7BV%7D%20%5C%5C%20%5C%5C%20V%20%26%20%3D%20%5Cfrac%7Bm%7D%7BD%7D%20%5C%5C%20%5C%5C%20%26%20%3D%20%5Cfrac%7B%28280.%5Ctext%7B%20g%7D%29%7D%7B%5Cleft%28%5Cdfrac%7B1.00%5Ctext%7B%20g%7D%7D%7B1%5Ctext%7B%20mL%7D%7D%5Cright%29%7D%20%5C%5C%20%5C%5C%20%20%26%20%3D%20280.%20%5Ctext%7B%20mL%7D%5Ccdot%20%5Cfrac%7B1%5Ctext%7B%20L%7D%7D%7B1000%5Ctext%7B%20mL%7D%7D%20%3D%200.280%5Ctext%7B%20L%20soln.%7D%5Cend%7Baligned%7D)
Hence, the molarity of the solution is:
![\displaystyle \begin{aligned} \text{M} &= \frac{\text{ mols solute}}{\text{L soln.}} \\ \\ & = \frac{(0.640\text{ mol})}{(0.280\text{ L soln.})} \\ \\ & = 2.29\text{ M} \end{aligned}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cbegin%7Baligned%7D%20%5Ctext%7BM%7D%20%26%3D%20%5Cfrac%7B%5Ctext%7B%20mols%20solute%7D%7D%7B%5Ctext%7BL%20soln.%7D%7D%20%5C%5C%20%5C%5C%20%26%20%3D%20%5Cfrac%7B%280.640%5Ctext%7B%20mol%7D%29%7D%7B%280.280%5Ctext%7B%20L%20soln.%7D%29%7D%20%5C%5C%20%5C%5C%20%26%20%3D%202.29%5Ctext%7B%20M%7D%20%5Cend%7Baligned%7D)
In conclusion, the solution is about 2.29 M.