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2 years ago

Drag each label to the correct location on the table sort the sentences based on weather thy are correct or incorrect

Physics

1 answer:

Marta_Voda [28]2 years ago

3 0

The statement that water boils at a temperature below 100 degrees in a pressure cooker is correct

<h3>What is freezing?</h3>

The term freezing refers to the temperature at which a liquid is turned into a solid.

The following is the sorting of the statements into those that are correct and incorrect.

Water boils at a temperature below 100 degrees at high altitudes - correct

Water expands on freezing - correct

Water contracts on freezing - incorrect

Water boils at a temperature below 100 degrees in a pressure cooker - correct

Water boils at 100 degrees under normal pressure - correct

Learn more about freezing:brainly.com/question/3121416?

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How can neptune have more mass than uranus but a smaller diameter?

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Neptunes' average density is larger than that of Uranus. Hope this helps!

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3 years ago

Water Cycle

Nostrana [21]

Answer:

True

no water ever leaves the planet

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3 years ago

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The hydraulic oil in a car lift has a density of 8.53 x 102 kg/m3. The weight of the input piston is negligible. The radii of th

navik [9.2K]

Answer:

(a) the input force is 36.56 N

(b) the input force is 37.49 N

Explanation:

Given;

density of hydraulic oil, ρ = 8.53 x 10² kg/m³

radius of plunger, r₁ = 0.135 m

radius of piston, r₂ = 5.43 x 10⁻³ m

Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;

$P =\frac{F}{A}$

Where;

P is pressure

F is force

A is circular area = πr²

$\frac{F_1}{A_1} =\frac{F_2}{A_2} \\\\F_2 = \frac{F_1*A_2}{A_1} =\frac{F_1* \pi r_2^2}{\pi r_1^2} = \frac{F_1* r_2^2}{ r_1^2} \\\\F_2 = \frac{22600*(5.43*10^{-3})^2 }{(0.135)^2}\\\\F_2 = 36.56 \ N$

Part (b) The input force needed to support 22600-N weight, when the bottom surface of the output plunger is 1.20 m above that of the input plunger

$P_2 = P_1 + \rho gh$

But, F = PA and A = πr²

$F_2 = F_1(\frac{A_2}{A_1} ) + \rho gh*A_2\\\\F_2 = F_1(\frac{r_2^2}{r_1^2} )+\rho gh(\pi r_2^2)\\\\F_2 = 22600(\frac{5.43*10^{-3}}{0.135})^2 \ + 853*9.8*1.2*\pi (5.43*10^{-3})^2\\\\F_2=36.56 + 0.93\\\\F_2 = 37.49 \ N$

4 0

3 years ago

A system does 506 kj of work, and loses 266 kj of heat to the surroundings. what is the change in internal energy of the system?

babunello [35]

Answer:

The change in internal energy of the system = -772kJ

Explanation:

Given :

Heat lost by the system , a = -266KJ

Workdone by the system, W = -506KJ

The first law of thermodynamics states that:

Change in internal energy = q + w

Substituting values into the equation

Change in internal energy = (-266KJ) + (-506KJ)

Change in internal energy = -722KJ

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3 years ago

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Write 3 – 4 sentences predicting the changes in electrostatic force, strong nuclear force, and the stability of a nucleus if the

mrs_skeptik [129]

Electrostatic force arises due the charges at rest.In a isolated atom there is three fundamental particles called electron,proton and neutron.the electron is negatively charged,proton is positively charged and the neutron is neutral.

Generally the force between electron and proton is attractive,there will be also repulsion between proton and proton.due to the strong nuclear forces atom main its stability In an stable atom the the neutron to proton ratio lies between 1 to 1.42.if the number of neutrons are increased more,the stability will be hampered resulting the decrease in nuclear force also.

As neutron is neutral,there will be no change in the electrostatic forces as there is no increment of charge.but when the neutron number is increased at that time the binding energy per nucleon is decreased which in turn affects the nuclear force which is a short range force.the nucleus becomes heavy and unstable which undergoes decay.

one thing we have to remember also that the nuclear force is spin dependent .so the change in neutron number affects the strong nuclear force which is the reason for its decrement.

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3 years ago