Answer:
distance is 3.428571 ×
m
potential is 342.857143 ×
kV
kinetic energy is 713.571429 ×
KeV
Explanation:
Given data
diameter = 2.10 m
charge = 40.0 C
to find out
potential and distance from its center and kinetic energy
solution
we know diameter = 2.10 m so radius will be = 2.10 / 2 = 1.05 m and charge = 40 C
so potential = KQ/R
here K is constant with value = 9×
Nm²C²
so potential = 9×
(40) / 1.05
potential = 342.857143 ×
V
so potential is 342.857143 ×
kV
and
in 2nd part we find radius
potential = KQ / R
put the value
105 ×
= 9×
( 40 ) / R
R = 3.428571 ×
m
so distance is 3.428571 ×
m
and
in 3rd part
we find KE
so change in KE = change in V
so KE 2 - KE 1 = q (V2 - V1)
KE2 - 0 = 3 ( 342.857143 ×
- 105 )
so kinetic energy is 713.571429 ×
KeV
Answer:
Increasing the number of slits not only makes the diffraction maximum sharper, but also much more intense. If a 1 mm diameter laser beam strikes a 600 line/mm grating, then it covers 600 slits and the resulting line intensity is 90,000 x that of a double slit. Such a multiple-slit is called a diffraction grating.
· free fall is any motion of a body where gravity is the only forceacting upon it. In the context of general relativity, where gravitation is reduced to a space-time curvature, a body in free fall has no force acting on it.
A. NaOH
B. PbNO3
C. FeSO4
D. P2O3
E. CSe2
F. HC2H3O2
G. HCIO
H. H2SO4