Question

A 8.01 nC charge is located 1.90 m from a 3.86 nC point charge. (a) Find the magnitude of the electrostatic force that one charge exerts on the other.

Answer 1

Explanation:

Given that,

Charge 1, $q_1=8.01\ nC=8.01\times 10^{-9}\ C$

Charge 2, $q_2=3.86\ nC=3.86\times 10^{-9}\ C$

Distance between charges, d = 1.9 m

We need to find the electrostatic force that one charge exerts on the other. It is given by :

$F=k\dfrac{q_1q_2}{d^2}$

$F=9\times10^9\times\dfrac{8.01\times 10^{-9}\times 3.86\times 10^{-9}}{(1.9)^2}$

$F=7.70\times 10^{-8}\ N$

So, the magnitude of electric force that one charge exerts on the other charge is $7.70\times 10^{-8}\ N$. Hence, this is the required solution.