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crimeas [40]
2 years ago
12

Line mn is parallel to line pq, mp is perpendicular to mn, and nqis perpendicular to pq. consider each statement and determine w

hether it is true or false. circle the correct answer. options:
Mathematics
1 answer:
Maurinko [17]2 years ago
5 0

The true statements are:

  • Lines mn and pq have the same slope
  • The product of the slopes of mn and mp is -1

<h3>How to determine the true statements?</h3>

The lines are given as:

Lines mn, pq, mp, mn, nq and pq

From the question, the lines are either parallel lines or perpendicular lines

As a general rule,

Parallel lines have equal slope

This means that:

Lines mn and pq have the same slope

Assume two perpendicular lines have slopes m and n.

The relationship between their slopes is:

m * n = -1

This means that:

The product of the slopes of perpendicular lines mn and mp is -1

Hence, the true statements are (a) and (c)

Read more about parallel and perpendicular lines at:

brainly.com/question/7197064

#SPJ1

<u>Complete question</u>

Line mn is parallel to line pq, mp is perpendicular to mn, and nq is perpendicular to pq. consider each statement and determine whether it is true or false. circle the correct answer.

Pptions:

  • Lines mn and pq have the same slope
  • The slope of line pq is undefined.
  • The product of the slopes of mn and mp is -1
  • Lines mp and mq are parallel.

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Select all the expressions that have a value of 22 - 33 +29.
AysviL [449]

Answer:

B. and E.

Step-by-step explanation:

2^(2)-3^(3)+29 = 6

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3 years ago
The toll on a highway is based on the number of miles driven. If the toll on a 15-mile stretch of highway is $0.60, find the cos
Crank

Answer:

$3.20

Step-by-step explanation:

We have

15-mile stretch = $0.60

80-mile stretch = x

Cross Multiply

15 × x = 80 × $0.60

x = 80 × $0.60/15

x = $3.20

Hence, the cost to drive a 80-mile stretch is $3.20

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3 years ago
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Step-by-step explanation:

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4 years ago
Divide x4 + 7 by x - 3.. A] x³ - 3x² - 9x - 27 R 88. B] x³ + 3x² + 9x - 27 R -74. C] x³ + 3x² + 9x + 27 R 88
Nastasia [14]
<span> divide a polynomial p(x) by (x-3). Add and subtract the multiple of (x-3) that has the same highest-power term as p(x), then simplify to get a smaller-degree polynomial r(x) plus multiple of (x-3). </span>

<span>The multiple of (x-3) that has x^4 as its leading term is x^3(x-3) = x^4 - 3x^3. So write: </span>

<span>x^4 + 7 = x^4 + 7 + x^3(x - 3) - x^3(x - 3) </span>
<span>= x^4 + 7 + x^3(x - 3) - x^4 + 3x^3 </span>
<span>= x^3(x - 3) + 3x^3 + 7 </span>

<span>That makes r(x) = 3x^3 + 7. Do the same thing to reduce r(x) by adding/subtracting 3x^2(x - 3) = 3x^3 - 9x^2: </span>

<span>= x^3(x - 3) + 3x^3 + 7 + 3x^2(x - 3) - (3x^3 - 9x^2) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 </span>

<span>Again to reduce 9x^2 + 7: </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x^2 + 7 + 9x(x - 3) - (9x^2 - 27x) </span>
<span>= x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27x + 7 </span>

<span>And finally write 27x + 7 as 27(x - 3) + 88; </span>
<span>x^4 + 7 = x^3(x - 3) + 3x^2(x - 3) + 9x(x - 3) + 27(x - 3) + 88 </span>

<span>Factor out (x - 3) in all but the +88 term: </span>
<span>x^4 + 7 = (x - 3)(x^3 + 3x^2 + 9x + 27) + 88 </span>

<span>That means that: </span>
<span>(x^4 + 7) / (x - 3) = x^3 + 3x^2 + 9x + 27 with a remainder of 88</span>
3 0
3 years ago
Read 2 more answers
Which ordered pairs are solutions to the inequality 2x+y&gt;−4?
alexgriva [62]

Answer:

The ordered pairs are (5,-12), (-1,-1).

Step-by-step explanation:

Given : Inequality 2x+y>-4

To find : Which ordered pairs are solutions to the inequality ?

Solution :

We put the given options the point which satisfied the equation is the solution.

Inequality 2x+y>-4

1) (5,-12)

2(5)+(-12)>-4

10-12>-4

-2>-4

It is true.

2) (-1,-1)

2(-1)+(-1)>-4

-2-1>-4

-3>-4

It is true.

3) (-3,0)

2(-3)+(0)>-4

-6+0>-4

-6>-4

It is false.

4) (4,-12)

2(4)+(-12)>-4

8-12>-4

-4>-4

It is false.

Therefore, The ordered pairs are (5,-12), (-1,-1).

4 0
4 years ago
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