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2 years ago

SOMEONE PLEASE HELP!! ITS ALMOST DUE!! ILL MARK BRAINLIEST!!!

Mathematics

1 answer:

PtichkaEL [24]2 years ago

6 0

Answer:

5.8

Step-by-step explanation:

c=(square root of 5^2 + 3^2)

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When x = 3 and y = 5, by how much does the value of 3x2 – 2y exceed the value of 2x2 – 3y ?

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Answer:

Step-by-step explanation:

${3x}^{2} - 2y \\ 3 { \times 3}^{2} - 2 \times 5 \\ 27 - 10 = 17$

${2x}^{2} - 3y \\ 2 \times {3}^{2} - 3 \times 5 \\ 12 - 15 = - 3$

$17 - 3 = 14$

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2 years ago

In a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99. A nonprofit community health organizatio

Oksi-84 [34.3K]

Answer:

Brand A = 21 heart-rate watches.

Brand B = 13 heart-rate watches.

Step-by-step explanation:

Let A be the number of Brand A heart watches and B be the number of Brand B heart watches.

We have been given that a nonprofit community health organization purchased 34 heart-rate watches for use at a wellness center.

We can represent this information in an equation as:

$A+B=34...(1)$

We have been given that in a certain year, brand A of heart-rate watch cost $39.99 and brand B cost $59.99 and the organization spent $1619.66 for the watches.

We can represent this information in an equation as:

$39.99*A+59.99*B=1619.66...(2)$

We will use substitution method to solve our system of equations.

From equation (1) we will get,

$A=34-B$

Substituting $A=34-B$ in equation(2) we will get,

$39.99*(34-B)+59.99*B=1619.66$

$1359.66-39.99*B+59.99*B=1619.66$

$-39.99*B+59.99*B=1619.66-1359.66$

$20*B=260$

$B=\frac{260}{20}$

$B=13$

Therefore, the organisation purchased 13 heart-rate watches of brand B.

Now let us substitute B=13 in equation (1).

$A+13=34$

$A+13-13=34-13$

$A=21$

Therefore, the organisation purchased 21 heart-rate watches of brand A.

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2 years ago