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lutik1710 [3]
3 years ago
5

SOMEONE PLEASE HELP!! ITS ALMOST DUE!! ILL MARK BRAINLIEST!!!

Mathematics
1 answer:
PtichkaEL [24]3 years ago
6 0

Answer:

5.8

Step-by-step explanation:

c=(square root of 5^2 + 3^2)

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A.The distance around the circle

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I feed to find the circumference
fgiga [73]

answer:

131.88 inches

step-by-step explanation:

  • know the formula: 2πr
  • now plug in what we have

2πr = circumference

2(21)(3.14)

= 131.88

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A circular racetrack has a diameter of 1/2 mile. How far does a car travel in one lap around the track? Round to the nearest ten
dlinn [17]
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Circular racetrack with a diameter of 1/2 mile

Find: how far does a car travel in one lap around the track?

We need to find the circumference of the racetrack.

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7 0
3 years ago
Ann is adding water to a swimming pool at a constant rate. The table below shows the amount of water in the pool after different
N76 [4]

Answer:

(a)  As time increases, the amount of water in the pool increases.

     11 gallons per minute

(b)  65 gallons

Step-by-step explanation:

From inspection of the table, we can see that <u>as time increases, the amount of water in the pool increases</u>.

We are told that Ann adds water at a constant rate.  Therefore, this can be modeled as a linear function.  

The rate at which the water is increasing is the <em>rate of change</em> (which is also the <em>slope </em>of a linear function).

Choose 2 ordered pairs from the table:

\textsf{let}\:(x_1,y_1)=(8, 153)

\textsf{let}\:(x_2,y_2)=(12,197)

Input these into the slope formula:

\textsf{slope}\:(m)=\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{197-153}{12-8}=\dfrac{44}{4}=11

Therefore, the rate at which the water in the pool is increasing is:

<u>11 gallons per minute</u>

To find the amount of water that was already in the pool when Ann started adding water, we need to create a linear equation using the found slope and one of the ordered pairs with the point-slope formula:

y-y_1=m(x-x_1)

\implies y-153=11(x-8)

\implies y-153=11x-88

\implies y=11x-88+153

\implies y=11x+65

When Ann had added no water, x = 0.  Therefore,

y=11(0)+65

y=65

So there was <u>65 gallons</u> of water in the pool before Ann starting adding water.

3 0
2 years ago
Read 2 more answers
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