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3 years ago

6

Write the trigonometric expression as an algebraic expression in u. cos (sin-1 u)

1 answer:

harkovskaia [24]3 years ago

3 0

Cos(arcsin(u)) = √(1 - u²)

_____
You want cos(α) where sin(α) = u.
You know that
cos(α)² + sin(α)² = 1
cos(α)² = 1 - sin(α)² = 1 - u²
cos(α) = √(1 - u²)

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Please help me ASAP!!!! It is greatly appreciated!!! Will mark as Brainliest!!!!

Karo-lina-s [1.5K]

Answer: 5/4

Step-by-step explanation:

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3 years ago

I'd appreciate it if anyone could help me!

kvv77 [185]

let's recall that corresponding angles are equal, thus 105° twins, also let's recall that a flat-line has 180°.

since the two sides stemming from Ɣ are twins, the angles they make at the base are also twins, bearing in mind that a triangle has a sum of all interior angles of 180°.

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3 years ago

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BARSIC [14]

(1/3) bag = (1/4) lb.
multiply by 3 on both sides to get 1 full bag.
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3 years ago

The first term of a geometric sequence is 15, and the 5th term of the sequence is <img src="https://tex.z-dn.net/?f=%5Cfrac%7B24

sladkih [1.3K]

The geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

Explanation:

Given that the first term of the geometric sequence is 15

The fifth term of the sequence is $\frac{243}{125}$

We need to find the 2nd, 3rd and 4th term of the geometric sequence.

To find these terms, we need to know the common difference.

The common difference can be determined using the formula,

$a_n=a_1(r)^{n-1}$

where $a_1=15$ and $a_5=\frac{243}{125}$

For $n=5$ , we have,

$\frac{243}{125}=15(r)^4$

Simplifying, we have,

$r=\frac{3}{5}$

Thus, the common difference is $r=\frac{3}{5}$

Now, we shall find the 2nd, 3rd and 4th terms by substituting $n=2,3,4$ in the formula $a_n=a_1(r)^{n-1}$

For $n=2$

$a_2=15(\frac{3}{5} )^{1}$

$=9$

Thus, the 2nd term of the sequence is 9

For $n=3$ , we have,

$a_3=15(\frac{3}{5} )^{2}$

$=15(\frac{9}{25} )$

$=\frac{27}{5}$

Thus, the 3rd term of the sequence is $\frac{27}{5}$

For $n=4$ , we have,

$a_4=15(\frac{3}{5} )^{3}$

$=15(\frac{27}{25} )$

$=\frac{81}{25}$

Thus, the 4th term of the sequence is $\frac{81}{25}$

Therefore, the geometric sequence is $15,9,\frac{27}{5},\frac{81}{25}, \frac{243}{125}$

5 0

3 years ago

Rathaus thinks all the factors of even numbers are even which explains wether Rathan is correct

scoundrel [369]

Answer:

Incorrect

Step-by-step explanation:

It is incorrect because all even numbers have a factor of 1.

That is odd.

6 0

3 years ago

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