Explanation:
It is given that,
The total mass of the wagon, rider and the rock is 99 kg
The mass of the rock is 0.261 kg.
The initial speed of the wagon, u = 0.519 m/s
Speed of the rock, u' = 15.9 m/s
(a) Let v is the speed of the wagon after the rock is thrown directly in forward direction.
The momentum will remain constant. Using the conservation of momentum as :
v = 0.22 m/s
(b) Let v' is the speed of the wagon after the rock is thrown directly in opposite direction, u' = -15.9 m/s
v' = 0.304 m/s
Hence, this is the required solution.
Answer:
2
Explanation:
Step 1: RxN
4Al + 3O₂ → Al₂O₃
Step 2: Balance RxN
We have 4 Al's and 6 O₂'s on the reactant side.
We need the same number of Al's and O₂'s on the product side.
4Al + 3O₂ → 2Al₂O₃
Answer:
Drawing the triangle:
H / x = tan 52.2 = 1.29
H / (4.6 - x) = tan 28.8 = .550
H = 1.29 x
H = .55 * 4.6 - .55 x
1.84 x = 2.53 combining equations
x = 1.38
4.6 - 1.38 = 3.22
Total base of triangle = 1.38 + 3.22 = 4.6
H / x = tan 52,2 = 1.29
H = 1.29 * 1.38 = 1.78 height of triangle
Check:
1.78 / 3.22 = tan 28.9
This agrees with the given value of 28.8
I Think The answer is d I hope it helps My friend Message Me if I’m wrong and I’ll change My answer and fix it for you
Um... This is not exactly physics...(Although, this school of thought is most likely Moral Relativism.)