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Natali [406]
3 years ago
10

Suppose you are asked to find the area of a rectangle that is 2.1-cm wide by 5.6-cm long. Your calculator answer would be 11.76

cm2 . Now suppose you are asked to enter the answer to two significant figures. (Note that if you do not round your answer to two significant figures, your answer will fall outside of the grading tolerance and be graded as incorrect.)
Physics
1 answer:
lianna [129]3 years ago
3 0

The area of a rectangle whose length is 5.6 cm and the width is 2.1 cm to two significant figures is 12 cm ².

<h2>Further Explanation </h2><h3>Area </h3>
  • Area is a measure of how much space is occupied by a given shape.
  • Area of a substance is determined by the type of shape in question.

For example;

Area of a rectangle is given by; Length multiplied by width

Area of a triangle = 1/2 x base x height

Area of a circle = πr². where r is the radius of a circle,

Area of a square = S², Where s is the side of the square.etc.

Perimeter

  • Perimeter is defined as the distance along a two dimension shape.  Perimeter of different shapes is given by different formulas
  • For example

The perimeter of a rectangle = 2(length+width)

The perimeter of a triangle = a+b+c; where a, b and c are the sides of the triangle. etc.

In this question

The rectangle has a;

Length = 5.6 cm

Width = 2.1 cm

Area of a rectangle = length × width

                               = 2.1 cm × 5.6 cm

                               = 11.76 cm²

The area of the rectangle to two significant figures is 12 cm²

Keywords; Area, Area of a rectangle

<h3>Learn more about;</h3>
  • Area: brainly.com/question/1322653
  • Perimeter: brainly.com/question/1322653
  • Area of a rectangle: brainly.com/question/1322653

Level: Middle school

Subject; Mathematics

Topic: Area and Perimeter

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a)       a = 3.72 m / s², b)    a = -18.75 m / s²

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a) Let's use kinematics to find the acceleration before the collision

             v = v₀ + at

as part of rest the v₀ = 0

             a = v / t

Let's reduce the magnitudes to the SI system

              v = 115 km / h (1000 m / 1km) (1h / 3600s)

              v = 31.94 m / s

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l

et's calculate

             a = 31.94 / 8.58

             a = 3.72 m / s²

b) For the operational average during the collision let's use the relationship between momentum and momentum

            I = Δp

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            F = \frac{m ( v_f - v_o)}{t}

            F = m [16.66 - 31.94] / 0.815

            F = m (-18.75)

Having the force let's use Newton's second law

            F = m a

            -18.75 m = m a

             a = -18.75 m / s²

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