Fe=k|q1q2| / r^2
(k is the electrostatic constant which has a value of 8.99x10^9 Nm^2/c^2, r is the distance between the charges and q is the quantity of the charges.)
Answer:
F₁ = 4 F₀
Explanation:
The force applied on the string by the ball attached to it, while in circular motion will be equal to the centripetal force. Therefore, at time t₀, the force on ball F₀ is given as:
F₀ = mv₀²/r --------------- equation (1)
where,
F₀ = Force on string at t₀
m = mass of ball
v₀ = speed of ball at t₀
r = radius of circular path
Now, at time t₁:
v₁ = 2v₀
F₁ = mv₁²/r
F₁ = m(2v₀)²/r
F₁ = 4 mv₀²/r
using equation (1):
<u>F₁ = 4 F₀</u>
The mass on the spring is bouncing.
We would call it a wave-like motion, except that it all stays in the same place. But, just like a wave, moving from the highest position to the lowest position
is one-half of a full wiggle.
(The other half consists of moving from the lowest position back up to the
highest position, where it started from.
So, half of the wave-like motion takes 0.6 seconds.
A full cycle of the wave motion ... the actual period of the bounce,
is double that much time . . .
1.2 seconds.
Answer:
f = 735 Hz
Explanation:
given,
Person distance from speakers
r₁ = 4.1 m r₂ = 4.8 m
Path difference
d = r₂ - r₁ = 4.8 - 4.1 = 0.7 m
For destructive interference

where, n = 1, 3,5..
we know, λ = v/f

v is the speed of the sound = 343 m/s
f is the frequency

for n = 1

f = 245 Hz
for n = 3

f = 735 Hz
Hence,the second lowest frequency of the destructive interference is 735 Hz.