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tatyana61 [14]
3 years ago
13

Last year, the school library had a total of x books. Over the summer, the library acquired another 35 books and now has a total

of 2,943 books. Which equation could be used to find x, the number of books the library had last year?
Mathematics
1 answer:
ki77a [65]3 years ago
6 0

Answer:

the equation is x= 2908

Step-by-step explanation:

you need to find the number of books they had by taking the new total and subtract it by the number they add and that would equal x in the problem

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What is the cubed root of 27?
lianna [129]

Answer:

Then answer is 3

Step-by-step explanation:

cube root = ³√27

3×3×3 = 3³ = 27

6 0
3 years ago
Read 2 more answers
Our club has 25 members, and wishes to pick a president, secretary, and treasurer. In how many ways can we choose the officers,
Rus_ich [418]

Answer:

13800

Step-by-step explanation:

The order of the members is important (because each selected member will receive a different position), thus we then need to use the definition of permutation.

There are 25 members, of which 3 are selected.

\begin{array}{l}n=25 \\r=3\\end{array}

Evaluate the definition of a combination:

P(25,3)=\frac{25 !}{(25-3) !}=\frac{25 !}{22 !}=25 \cdot 24 \cdot 23=13800

8 0
3 years ago
A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 2
Shalnov [3]

Answer:

The expected winnings for a person buying 1 ticket is -0.2.                  

Step-by-step explanation:

Given : A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each. If 20000 tickets are sold at 25 cents each, find the expected winnings for a person buying 1 ticket.

To find : What are the expected winnings?    

Solution :

There are one first prize, 2 second prize and 20 third prizes.

Probability of getting first prize is \frac{1}{20000}

Probability of getting second prize is \frac{2}{20000}

Probability of getting third prize is \frac{20}{20000}

A raffle offers a first prize of $1000, 2 second prizes of $300, and 20 third prizes of $10 each.

So, The value of prizes is

\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10

If 20000 tickets are sold at 25 cents each i.e. $0.25.

Remaining tickets = 20000-1-2-20=19977

Probability of getting remaining tickets is \frac{19977}{20000}

The expected value is

E=\frac{1}{20000}\times 1000+\frac{2}{20000}\times 300+\frac{20}{20000}\times 10-\frac{19977}{20000}\times 0.25

E=\frac{1000+600+200-4994.25}{20000}

E=\frac{-3194.25}{20000}

E=-0.159

Therefore, The expected winnings for a person buying 1 ticket is -0.2.

3 0
2 years ago
14/38 simplified? Thanks!
ira [324]
14/38 simplified would be 7/19
5 0
3 years ago
Need Help. Please! Will Give Brainliest!
Sindrei [870]
The answer is 45.5 please give Brainliest!

4 0
3 years ago
Read 2 more answers
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