Question

I need help ,,, and tahnks☺

Answer 1

Pythagora: 20^2=(4x)^2+(3x^2)
400=16x^2+9x^2
x^2=400/25
x^2=16
x=4

Answer 2

We can use the Pythagoras theorem:

leg 1² + leg 2² = hypotenuse²
(4x)² + (3x)² = 20²
16x² + 9x² = 400
combine like terms
25x² = 400

divide by 25 on both sides to isolate x²
$\frac{25x^2}{25} = \frac{400}{25}$
25 and 25 cancels out

x² = 16

Take square root on either sides tot find the value
$\sqrt{x^2} = \sqrt{16}$
x = +/- 4

Cancels -4 because lengths cannot be in negative.

x = 4

check:
(4 × 4)² + (3 × 4)² = 20²
(16)² + (12)² = 400
256 + 144 = 400
400 = 400