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LUCKY_DIMON [66]
3 years ago
10

I need help ,,, and tahnks☺

Mathematics
2 answers:
Mashcka [7]3 years ago
6 0
Pythagora: 20^2=(4x)^2+(3x^2)
400=16x^2+9x^2
x^2=400/25
x^2=16
x=4
Lubov Fominskaja [6]3 years ago
4 0
We can use the Pythagoras theorem:

leg 1² + leg 2² = hypotenuse²
(4x)² + (3x)² = 20²
16x² + 9x² = 400
combine like terms
25x² = 400

divide by 25 on both sides to isolate x²
\frac{25x^2}{25} =  \frac{400}{25}
25 and 25 cancels out

x² = 16

Take square root on either sides tot find the value
\sqrt{x^2} = \sqrt{16}
x = +/- 4

Cancels -4 because lengths cannot be in negative.

x = 4

check:
(4 × 4)² + (3 × 4)² = 20²
(16)² + (12)² = 400
256 + 144 = 400
400 = 400
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Answer:

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Step-by-step explanation:

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So, let (x_{2} , y_{2} ) be the coordinates of the endpoint you are looking for.

x_{1} = -9  and y_{1}  = 7

(\frac{-9 + x_{2} }{2} , \frac{7 + y_{2} }{2} ) = (10, -3)

\frac{-9 + x_{2} }{2}  = 10           \frac{7 + y_{2} }{2}  = -3

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Step-by-step explanation:

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