Ask question

Ask question

All categories

2 years ago

7

Question 7 of 10

1 answer:

jok3333 [9.3K]2 years ago

5 0

Step-by-step explanation:

$= 3 \sqrt{6}$

$= \sqrt{ {3}^{2}.6 }$

$= \sqrt{9.6}$

$= \sqrt{54}$

The answer is A.

You might be interested in

Help easy math!!!!!!!!! (:

7nadin3 [17]

H=3v/b should be the correct answer

3 0

4 years ago

Read 2 more answers

In Store A, a book that regularly sells for $24.99 is on sale at 15% off. In Store B the same book regularly sells for $27.99 an

stealth61 [152]

Answer: Store B

Step by Step
divide the the normal price of the book by four to get the amount of the book on sale in store B which is $21. To get the answer for Store A divide the normal price of the book by ten then divide the amount you get by 2 and add the two amounts up to get the the amount of the book on sale which is $21.26

8 0

3 years ago

9 less than 5 × a number that is equal to -30

pickupchik [31]

I believe the equation would be 5x-9=-30

5 0

4 years ago

Brady made a scale drawing of a rectangular swimming pool on a coordinate grid. The points (-20, 25), (30, 25), (30, -10) and (-

djverab [1.8K]

Answer:

Length = 50 units

width = 35 units

Step-by-step explanation:

Let A, B, C and D be the corner of the pools.

Given:

The points of the corners are.

$A(x_{1}, y_{1}})=(-20, 25)$

$B(x_{2}, y_{2}})=(30, 25)$

$C(x_{3}, y_{3}})=(30, -10)$

$D(x_{4}, y_{4}})=(-20, -10)$

We need to find the dimension of the pools.

Solution:

Using distance formula of the two points.

$d(A,B)=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ ----------(1)

For point AB

Substitute points A(30, 25) and B(30, 25) in above equation.

$AB=\sqrt{(30-(-20))^{2}+(25-25)^{2}}$

$AB=\sqrt{(30+20)^{2}}$

$AB=\sqrt{(50)^{2}$

AB = 50 units

Similarly for point BC

Substitute points B(-20, 25) and C(30, -10) in equation 1.

$d(B,C)=\sqrt{(x_{3}-x_{2})^{2}+(y_{3}-y_{2})^{2}}$

$BC=\sqrt{(30-30)^{2}+((-10)-25)^{2}}$

$BC=\sqrt{(-35)^{2}}$

BC = 35 units

Similarly for point DC

Substitute points D(-20, -10) and C(30, -10) in equation 1.

$d(D,C)=\sqrt{(x_{3}-x_{4})^{2}+(y_{3}-y_{4})^{2}}$

$DC=\sqrt{(30-(-20))^{2}+(-10-(-10))^{2}}$

$DC=\sqrt{(30+20)^{2}}$

$DC=\sqrt{(50)^{2}}$

DC = 50 units

Similarly for segment AD

Substitute points A(-20, 25) and D(-20, -10) in equation 1.

$d(A,D)=\sqrt{(x_{4}-x_{1})^{2}+(y_{4}-y_{1})^{2}}$

$AD=\sqrt{(-20-(-20))^{2}+(-10-25)^{2}}$

$AD=\sqrt{(-20+20)^{2}+(-35)^{2}}$

$AD=\sqrt{(-35)^{2}}$

AD = 35 units

Therefore, the dimension of the rectangular swimming pool are.

Length = 50 units

width = 35 units

7 0

3 years ago

‏‏‎ ‎‎‎‎‎‎‎‎‎‎‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎ ‎‏‏‎

Marizza181 [45]

Answer:

2x + 2x + x - 8 = 4 (x + 2)

x = 16

Step-by-step explanation:

Because that's a square, the perimeter would be 4s where s is the measure of the side:

2x + 2x + x - 8 = 4 (x + 2)

To solve, refer below:

2x + 2x + x - 8 = 4x + 8

5x - 8 = 4x + 8

5x = 4x + 8 + 8

x = 16

3 0

3 years ago