8[2] + 6[2] = c[2]
64 + 36 = c[2]
100 = c[2]
c = 10
8 + 6 + 10 = 24 units
Answer:
see explaination
Step-by-step explanation:
Using the formulla that
sum of terms number of terms sample mean -
Gives the sample mean as \mu=17.954
Now varaince is given by
s^2=\frac{1}{50-1}\sum_{i=1}^{49}(x_i-19.954)^2=9.97
and the standard deviation is s=\sqrt{9.97}=3.16
b) The standard error is given by
\frac{s}{\sqrt{n-1}}=\frac{3.16}{\sqrt{49}}=0.45
c) For the given data we have the least number in the sample is 12.0 and the greatest number in the sample is 24.1
Q_1=15.83, \mathrm{Median}=17.55 and Q_3=19.88
d) Since the interquartile range is Q_3-Q_1=19.88-15.83=4.05
Now the outlier is a number which is greater than 19.88+1.5(4.05)=25.96
or a number which is less than 15.83-1.5(4.05)=9.76
As there is no such number so the given sample has no outliers
Answer:
a = 86y
Step-by-step explanation:
Given:
Number of applicants per year = 86
Find:
Equation represent total applicants
Computation:
Assume;
Total number of years = y
Total number of applicants = a
So,
Total number of applicants = Number of applicants per year x Total number of years
a = 86 x y
a = 86y
Answer:
x=3
Step-by-step explanation:
(11-3)+3x+1 = 5x+3
8+3x+1 = 5x+3
9+3x= 5x+3
6=2x
x=3
