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Kay [80]
2 years ago
15

Define coefficiend, base and index of an algebraic term with an example​

Mathematics
1 answer:
murzikaleks [220]2 years ago
7 0

Step-by-step explanation:

a number used multiplier variable

example 6z menas 6 times z and z is a variable so sixes coefficient variable with no number have a question of one example X is a really 1x

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There are 4 students on a team for a relay race. How many teams can be made from 29 students?
Kaylis [27]

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7 teams, hoped this helped :)

Step-by-step explanation:

8 0
3 years ago
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No links, provide explanation.
a_sh-v [17]

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C: 18

Step-by-step explanation:

6 0
3 years ago
Assume that when adults with smartphones are randomly​ selected, 57​% use them in meetings or classes. If 8 adult smartphone use
maxonik [38]

Answer:  0.0575

Step-by-step explanation:

Binomial probability distribution :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(X) is the probability of getting success in x trials, n is the total number of trials and p is the probability of success in each trial ( in  decimal ).

Given : The probability that adults use smartphones  in meetings or classes = 0.57

Sample size : n= 8

Now, the probability that exactly 2 of them use their smartphones in meetings or classes :-

P(x)=^8C_2(0.57)^2(0.43)^{6}\\\\=\dfrac{8!}{(8-2)!2!}(0.57)^2(0.43)^{6}\\\\=0.0575067039294\approx0.0575

Hence, the required probability = 0.0575

6 0
3 years ago
A man spend 3/5 of his money and has$ 90 left . how much did he have initially​
Slav-nsk [51]

Answer:

225 I believe because if he has $90 that is 2/5 so add another 90 whitch is 2/5 as well and divide 90 by 2 and to get 45 which all adds up to 225

6 0
3 years ago
A spherical pressure vessel is required to contain 1.5 m3 of compressed natural gas at 22 MPa . If the tank is made of A516 grad
kifflom [539]

Answer:

The required thickness of the tank wall is 87.7668 mm.

Step-by-step explanation:

Given :

Volume of vessel is V=1.5 m³.

A spherical pressure vessel is of compressed natural gas at P=22 MPa.

If the tank is made of A516 grade 60 steel with a maximum normal stress 150 MPa.

i.e. \sigma_{max}=150\ Mpa

To find : What is the required thickness of the tank wall?

Solution :

The diameter of the vessel is given by,

\frac{d}{2}=\sqrt{\frac{3V}{4\pi} }

\frac{d}{2}=\sqrt{\frac{3\times 1.5}{4\times 3.14}}

\frac{d}{2}=\sqrt{\frac{4.5}{12.56}}

\frac{d}{2}=\sqrt{0.358}

\frac{d}{2}=0.598

d=1.196\ m

Convert into mm,

d=1.196\times 1000=1196.82\ mm

The thickness of the wall tank is given by,

t=\frac{Pd}{2\sigma}

t=\frac{22\times 1196.82}{2\times 150}

t=\frac{26330.04}{300}

t=87.7668

Therefore, the required thickness of the tank wall is 87.7668 mm.

4 0
4 years ago
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