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snow_tiger [21]
3 years ago
15

A circle has an initial radius of 50 ft when the radius begins decreasing at the rate of 5 5 ​ft/min. What is the rate in the ch

ange of area at the instant that the radius is 26 26 ​ft?
Mathematics
1 answer:
gavmur [86]3 years ago
6 0

Answer:

  -816.8 ft²/min

Step-by-step explanation:

The rate of change of area is the product of the rate of change of radius and the circumference of the circle. At the time of interest, ...

  dA/dt = C·dr/dt = 2πr·dr/dt

  dA/dt = 2π·(26 ft)(-5 ft/min)

  dA/dt = -260π ft²/min ≈ -816.8 ft²/min

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bija089 [108]

Answer:

2

Step-by-step explanation:

6 0
3 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
2 years ago
2 1/4 ⋅ 1 2/3<br> as a mixed number
Gemiola [76]

Answer:

3\frac{3}{4}

Step-by-step explanation:

We have two mixed numbers and are asked to multiply them together.

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Multiply the whole number by the denominator and add the numerator.

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\frac{9*5}{4*3}

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5 0
3 years ago
Foggy Optics, Inc., makes laboratory microscopes. Setting up each production run costs $2500. Insurance costs, based on the aver
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Answer: 4

Step-by-step explanation:

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total number of microscopes = total number of runs * microscopes per run

now we have each run to cost 2500, therefore:

run costs = 2500 * total runs = 2500*N

we also have insurance and storage costs (note the average thats why we divide by 2):

storage costs = 20* microscopes per run /2 = 20*N/2

insurance costs = 15 * microscopes per run = 15*N

the costs are:

costs = run costs + storage + insurance

now the comany sells 1600 microscopes a year, so in order to figure out the number of microscopes per run we divide 1600 by the total number of runs N and replace in the costs

costs = 2500N + 40000/N => C(N) = 2500N + 40000/N

now derivate the function with respect to N and equal to 0:

\frac{d}{dN}(2500N + 40000/N) = 2500(1-16/N^2) \\\\  2500(1-16/N^2) = 0\\

this gives you two solutions, N = -4 which is not eligible (you cant make negative microscopes lol) and N = 4 which is the answer

have a nice day

4 0
3 years ago
Use the distributive property to create an equivalent expression to 40+4x
Ksivusya [100]
I think 2(2x+20) would work.
there are other ones like: 4(x+10)
5 0
3 years ago
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