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Effectus [21]
3 years ago
11

A certain bacteria culture grows at a rate if 18% everday. There are currently 420 bacteria. How many bacteria will there be on

day day 8
Mathematics
1 answer:
Anettt [7]3 years ago
6 0

Answer:

1579

Step-by-step explanation:

There is a particular formula you must use and it leads to this 420(1 + 0.18)^8=1579

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Find the simplified product. 2V5x^3(-3/10x^2)
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Step-by-step explanation:

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Answer: the answer is -2 1/3

Step-by-step explanation: it would be -2 1/3 because 5 + 2=7 and then add the 1/3 to make -7 1/3

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 Can you solve 2^x=e^(x+2)
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Although you haven't asked for the solution, here it is anyway:

2^x = e^(x+2)

x ln(2) = x+2

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Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140
Westkost [7]

Answer:

The amount each took home was 20 unit currency.

Step-by-step explanation:

We are given that Seven apple women, possessing respectively 20, 40, 60, 80, 100, 120, and 140  apples, went to market and sold all their apples at the same price, and each  received the same sum of money.

Formula  : a \times n + (n - 1), (a + b)\cdot n + (n - 2), (a + 2 \cdot b) \cdot n + (n - 3), (a + 3 \cdot b) \cdot n + (n - 4), (a + 4 \cdot b) \cdot n + (n - 5), (a + 5 \cdot b) \cdot n + (n - 6), (a + 6 \cdot b) \cdot n + (n - 7)

a \cdot n + (n - 1) = 20

(a + b) \cdot n + (n - 2)=40

(a + 2 \cdot b) \cdot n + (n - 3) = 60

(a + 3 \cdot b) \cdot n + (n - 4) = 80

(a + 4 \cdot b) \cdot n + (n - 5) = 100

(a + 5 \cdot b) \cdot n + (n - 6) = 120

(a + 6 \cdot b) \cdot n + (n - 7) = 140

On solving :

n = 7, a = 2, b = 3

So,

2 \times 7 + 6 = 20

5 \times 7 + 5=40

8 \times 7 + 4 = 60

11 \times 7 +  3 = 80

14 \times 7 + 2 = 100

17 \times 7 + 1 = 120

Based on market pricing if groups of apples are sold at 1 unit currency for 7, and extras are sold for 3 unit currency per extra 1, we have the amount :

2×1 + 6×3 = 20

5×1 + 5×3=20

8×1 + 4×3 = 20

11×1 +  3×3 = 20

14×1 + 2×3 = 20

17×1 + 1×3 = 20

20×1 = 20

Therefore, the amount each took home was 20 unit currency.

4 0
3 years ago
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