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Marizza181 [45]
2 years ago
6

5. Find the equation of the line that goes through the points (4,7) and (-2,-5)

Mathematics
1 answer:
Lelechka [254]2 years ago
8 0

Answer:

equation= y-y¹=m(x-x¹)

where m= gradient or slope

slope = <u>y²-y¹</u>

x²-x¹

= -<u>5-7</u>

-2-4

<u>-</u><u>1</u><u>2</u>

-6

= 2

equation= y-7=2(x-4)

y-7=2x-8

y= 2x-8+7

y=2x-1

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Vladimir79 [104]

Answer:

-6x-16

Step-by-step explanation:

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Kenny bought 20 packs of baseball cards. There are 12 cards in rack pack. How many cards did Kenny buy?
uranmaximum [27]
If Kenny bought 20 packs of baseball cards and there are 12 cards in a pack, you can calculate how many cards did Kenny buy using the following steps:

20 packs of cards * 12 cards in a pack = 20 * 12 = 240 cards

Result: Kenny bought 240 cards.
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Find the equation of all tangent lines having slope of -1 that are tangent to the curve y=(9)/(x+1)
fredd [130]

Answer:

f(x)=\frac9{x+1}\\ f'(x)=-\frac9{(x+1)^2}\\ f'(x)=-1\ \iff\ -\frac9{(x+1)^2}=-1\ \to \ \frac9{(x+1)^2}=1\ \to \ (x+1)^2=9\\ |x+1|=3\ \to \ x+1=3\ \vee\ x+1=-3\\ x_1=2\ \vee\ x_2=-4\\ f(x_1)=f(2)=\frac9{2+1}=3\\ f(x_2)=f(-4)=\frac9{-4+1}=-3

First tangent line:

y=f'(x_1)\cdot (x-x_1)+f(x_1)\ \to \ y=-1(x-2)+3\ \to \ y=-x+5

Second tangent line:

y=f'(x_2)\cdot (x-x_2)+f(x_2)\ \to \ y=-1(x+4)-3\ \to \ y=-x-7


Notice: slope of -1 means that both f'(x_1), \ f'(x_2) are equal to -1, so f'(x_1)=-1 \ and \ f'(x_2)=-1


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How do you find Find the value of x.
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Step-by-step explanation:

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2 years ago
Solve the system of equations by graphing: 2x + 3y = 2 6x + 18y = 9
cluponka [151]
The answer is  A: x=1/2 , y= 1/3

Solve the following system:
{2 x + 3 y = 2 | (equation 1)
{6 x + 18 y = 9 | (equation 2)

Swap equation 1 with equation 2:
{6 x + 18 y = 9 | (equation 1)
{2 x + 3 y = 2 | (equation 2)

Subtract 1/3 × (equation 1) from equation 2:
{6 x + 18 y = 9 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Divide equation 1 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x - 3 y = -1 | (equation 2)

Multiply equation 2 by -1:
{2 x + 6 y = 3 | (equation 1)
{0 x+3 y = 1 | (equation 2)

Divide equation 2 by 3:
{2 x + 6 y = 3 | (equation 1)
{0 x+y = 1/3 | (equation 2)

Subtract 6 × (equation 2) from equation 1:
{2 x+0 y = 1 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Divide equation 1 by 2:
{x+0 y = 1/2 | (equation 1)
v0 x+y = 1/3 | (equation 2)

Collect results:
Answer:  {x = 1/2, y = 1/3

7 0
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