The height of the object after 1 sec is 284 feet
<h3>Equation of height of an object</h3>
Given the equation of height of an object expressed as:
h(t) = -16t^2 + 300t
We are to find the height of the object after 1 sec. To do that, we will substitute t = 1 into the following expression
h(t) = -16t^2 + 300t
h(1) = -16(1)^2 + 300(1)
h(1) = -16 + 300
h(1) = 284ft
Hence the height of the object after 1 sec is 284 feet
Learn more on maximum height here: brainly.com/question/12446886
The equation looks like this
y≤ -1/3x + 4
And it looks like
Answer:
positive, its above 0
Step-by-step explanation:
The answer would be 2.16.
This is because the two negatives would cancel each other out when multiplying. This would basically make the question

.
Now 3.3 is definitely not less than 2.4, so the answer would be 2.16