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2 years ago

Find x. Do not round your answer 12 cm 6 cm 5 cm

Mathematics

1 answer:

Artyom0805 [142]2 years ago

7 0

The value of x from the given diagram is 16.6

<h3>Secant-secant theorem</h3>

In order to determine the value of x from the given figure, we will use the secant-secant theorem shown by the equation.

(6 +12) * 6 = (5 + x) * 5

Expand

36+72 = 25 + 5x

108 = 25 + 5x

5x = 108 - 25

5x = 83

x = 83/5

x = 16.6

Hence the value of x from the given diagram is 16.6

Learn more on secant-secant theorem here: brainly.com/question/26826991

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7x + y^2; if x = -4 and y = 5

const2013 [10]

Answer:

-3

Step-by-step explanation:

7x + y^2

subsitute

= 7x=7x-4= -28

=y^2=5^2= 25

-28 + 25= -3

8 0

3 years ago

How can you use expressions and diagrams to find total amounts in percent problems?

LenaWriter [7]

Answer: Identify the total amount of percent then calculate the total amount using addition expressions and diagrams calculate then, total amount using subtraction and expressions diagrams

Step-by-step explanation:hope it helps

6 0

3 years ago

Which statement is true about a negative number and its additive inverse?

MakcuM [25]

Answer:

B.) They are on opposite sides of zero on the number line.

stay safe and have a great day!

6 0

3 years ago

Read 2 more answers

READ QUESTION CAREFULLY, PLS ANSWER WITH WORKING

kotykmax [81]

Expressions for 'c' and 'd' in terms of 'a' will be $(d=4a)$ and $(c=a^2+8)$ .

In question number 12, it's given that $(a+\sqrt{8})^2$ can be written as $(c+d\sqrt{2})$ .

So the expression representing the situation will be,

$(a+\sqrt{8})^2=(c+d\sqrt{2})$

Now simplify the expression,

$a^2+8+2a\sqrt{8}=c+d\sqrt{2}$

$(a^2+8)+2a\sqrt{8}=(c+d\sqrt{2})$

$(a^2+8)+4a\sqrt{2}=(c+d\sqrt{2})$

Compare both the sides of the equation,

$c=a^2+8$

$4a\sqrt{2}=d\sqrt{2}$

$d=4a$

Therefore, $(d=4a)$ and $(c=a^2+8)$ will be the expressions for c and d in terms of a.

Learn more,

brainly.com/question/13030227

4 0

3 years ago

How do I use elimination for the equations-x+5y=20 and 12y= 2x+ 60?

Slav-nsk [51]

$\left\{\begin{array}{ccc}-x+5y=20\\12y=2x+60&\text{subtract 2x from both sides}\end{array}\right\\\left\{\begin{array}{ccc}-x+5y=20\\-2x+12y=60&\text{divide both sides by (-2)}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}-x+5y=20\\x-6y=-30\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-y=-10\to\boxed{y=10}\\\\\text{Put the value of y to the second equation:}\\\\x-6(10)=-30\\x-60=-30\qquad\text{add 60 to both sides}\\\boxed{x=30}\\\\Answer:\ \boxed{x=30\ and\ y=10\to(30,\ 10)}$

3 0

4 years ago