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k0ka [10]
3 years ago
5

I will give out brainliest answer this

Mathematics
2 answers:
Readme [11.4K]3 years ago
7 0
Pull factors would be freedom,job opportunities, and family and friends, rest is push factors.
Archy [21]3 years ago
3 0

Answer:

Step-by-step explanation:

jobs oppurtunitiesjefhf

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Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal. (Enter your answers as a comma-separated list.)
Gala2k [10]

Answer:

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

Step-by-step explanation:

Orthogonal vectors

Suppose we have two vectors:

v_{1} = (a,b,c)

v_{2} = (d,e,f)

Their dot product is:

(a,b,c).(d,e,f) = ad + be + cf

They are ortogonal is their dot product is 0.

Solving quadratic equations:

To solve this problem, we are going to need tosolve a quadratic equation.

Given a second order polynomial expressed by the following equation:

ax^{2} + bx + c, a\neq0.

This polynomial has roots x_{1}, x_{2} such that ax^{2} + bx + c = (x - x_{1})*(x - x_{2}), given by the following formulas:

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4a

Find all values of x such that (4, x, −6) and (2, x, x) are orthogonal.

(4,x,-6)(2,x,x) = 8 + x^{2} - 6x

These vectors are going to be orthogonal if:

x^{2} -6x + 8 = 0

This is a quadratic equation, in which a = 1, b = -6, c = 8. So

\bigtriangleup = 6^{2} - 4*1*8 = 4

x_{1} = \frac{-(-6) + \sqrt{4}}{2} = 4

x_{2} = \frac{-(-6) - \sqrt{4}}{2} = 2

The values of x that makes these vectors orthogonal are x = 2 and x = 4.

3 0
4 years ago
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