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3 years ago

I will give out brainliest answer this

Mathematics

2 answers:

Readme [11.4K]3 years ago

7 0

Pull factors would be freedom,job opportunities, and family and friends, rest is push factors.

Archy [21]3 years ago

3 0

Answer:

Step-by-step explanation:

jobs oppurtunitiesjefhf

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After a 60% reduction, you purchase a new sofa drink machine on sale for $312.

Varvara68 [4.7K]

Search up 0.60 x 312= 187.2, 187.2 + 312 = 499.2

4 0

3 years ago

sara wants to buy a necklace. the necklace has a list pice of $41 and the saels tax is 6%what will be the cost of the necklace a

gladu [14]

41multiply by 0.06+24.6
41+24.6=43.46

7 0

3 years ago

Read 2 more answers

A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a >0 and b >0 are constants and

Xelga [282]

Answer:

$V(t) = b^{(1-e^{-at})}$

Step-by-step explanation:

We are given the following information in the question:

$\displaystyle\frac{dV}{dt} = a (In b - In V) V$

where a > 0 and b > 0.

$\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}$

$V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}$

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0

3 years ago

What is the area of the regular hexagon ABCEF? Explain your reasoning.

Reil [10]

Answer:

1350 $\sqrt{3}$ units²

Step-by-step explanation:

The regular hexagon consists of 6 equiangular triangles

The area (A) of a equilateral triangle is calculated as

A = $\frac{s^2\sqrt{3} }{4}$ ( s is the side length )

Here s = 30 , then

A = $\frac{30^2\sqrt{3} }{4}$ = $\frac{900\sqrt{3} }{4}$ = 225 $\sqrt{3}$ units²

Thus the area of the regular hexagon is

area = 6 × 225 $\sqrt{3}$

= 1350 $\sqrt{3}$ units² ← exact value

≈ 2338.3 units² ( to 1 dec. place )

4 0

2 years ago

A coin is tossed 6 times. Find the probability P(of exactly 4 occurrences of heads).

Angelina_Jolie [31]

Let's draw!

H    1 T
HT    2       HT
HTHT 3         HTHT
HTHTHT 4       HTHTHT
HTHTHTHT 5       HTHTHTHT
HTHTHTHTHT 6    HTHTHTHTHT

You can count the probabilities using this.

HHHHTT
HHHTHT
HHTHHT
HHTHTH
HHHTTH
HTHHHT
HTTHHH
HTHTHH
HTHHTH

THHHHT
THHHTH
THHTHH
THTHHH
TTHHHH

Therefore, I think the probability is 14/64. Not sure so check my work.
14 combinations
64 outcomes (2+4+8+16+32+64 or 2^n)

7 0

3 years ago