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zysi [14]
3 years ago
9

The process of paying off the principal on the loan is called a(n) _____.

Mathematics
1 answer:
Alexeev081 [22]3 years ago
8 0
Its called amortization schedule
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Plz Help, I will give Brainliest!!!
vlada-n [284]

Answer:

can u zoom in ?????????????

Step-by-step explanation:

5 0
3 years ago
the difference between two numbers is 10 and their sum is four times the smaller number. find the two numbers
Vanyuwa [196]

Answer:

The smaller number is 5.

The bigger number is 15.

Step-by-step explanation:

Let the smaller number be x and the bigger number be x+10.

x+x+10 = 4x

2x+10 = 4x

10 = 4x-2x

2x = 10

x = 10÷2

  = 5

x+10 = 5+10

       = 15

8 0
3 years ago
The Correct Answer Is?
Alekssandra [29.7K]
Hello!

n<span>≤-1/2 means that n is less than the open circle, because an open circle means the variable can not be equal to that point. so your answer is: D

I hope this helps, and have a nice day.
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8 0
4 years ago
Two​ shooters, Rodney and​ Philip, practice at a shooting range. They fire rounds each at separate targets. The targets are mark
Sedaia [141]

Complete Question

Answer:

a

  SE  = 0.66}

b

-3.29 <  \mu_1 - \mu_2 <  -0.70  

Step-by-step explanation:

From the question we are told that

  The sample size is  n  = 60

   The first sample mean is  \= x _1  =  8

    The second sample mean is   \= x _2  =  10

    The first variance is  v_1 =  0.25

    The first variance is  v_2 =  0.55

Given that  the confidence level is 95% then the level of significance is 5% =  0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Generally the first standard deviation is  

     \sigma_1 =  \sqrt{v_1}

=>   \sigma_1 =  \sqrt{0.25}

=>   \sigma_1 =  0.5

Generally the second standard deviation is

     \sigma_2 =  \sqrt{v_2}

=>   \sigma_2 =  \sqrt{0.55}

=>   \sigma_2 =  0.742    

Generally the first standard error is

     SE_1  =  \frac{\sigma_1}{\sqrt{n} }

      SE_1  =  \frac{0.5}{\sqrt{60} }

     SE_1  =  0.06

Generally the second standard error is

     SE_2  =  \frac{\sigma_2}{\sqrt{n} }

      SE_2  =  \frac{0.742}{\sqrt{60} }

     SE_2  =  0.09

Generally the standard error of the difference between their mean scores is mathematically represented as    

      SE  =  \sqrt{SE_1^2 + SE_2^2 }

=>     SE  =  \sqrt{0.06^2 +0.09^2 }

=>     SE  = 0.66}

Generally 95% confidence interval is mathematically represented as  

      (\= x_1 -\= x_2) -(Z_{\frac{\alpha }{2} } *  SE) <  \mu_1 - \mu_2 <  (\= x_1 -\= x_2) +(Z_{\frac{\alpha }{2} } *  SE)

=> (8 -10) -(1.96 *  0.66) <  \mu_1 - \mu_2 <  (8-10) +(Z_{\frac{\alpha }{2} } *  0.66)  

=>  -3.29 <  \mu_1 - \mu_2 <  -0.70  

 

5 0
4 years ago
What is the end behavior of the graph?
ANTONII [103]

Answer:

As x approaches infinity f(x) approaches negative infinity.

Step-by-step explanation:

As you can see in the graph as x grows larger in the negative direction, the y increases in the negative direction too.

Thus:

\lim_{x \to -\infty} f(x) = -\infty

5 0
2 years ago
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