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Vlad [161]
3 years ago
14

Anyone know this at all?

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Answer:

  24.2

Step-by-step explanation:

You are given the hypotenuse and angle, and you want to find the length of the adjacent side.

The mnemonic SOH CAH TOA reminds you that the relation between angle and sides is ...

  Cos = Adjacent/Hypotenuse

  cos(41°) = x/32

  x = 32·cos(41°)

  x ≈ 24.2

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A bacteria population doubles in size every five hours after five hours the sample contains 2000 bacteria which equal the best m
Maurinko [17]

y=1000(x^2) is the answer :)

8 0
3 years ago
Please help i will give brainliest to the most accurate
Korolek [52]

Percent increase from 2000 to 2001 is 12% and from 2001 to 2002 is 12.6%. Thus period of 2001 to 2002 has higher increase percentage.

Solution:

Given that,

Total circulation of local newspaper in 2000 = 3250

Total circulation of local newspaper in 2001 = 3640

Total circulation of local newspaper in 2002 = 4100

As we can see 12% < 12.6%

So period of 2001 to 2002 has higher increase percentage.

6 0
3 years ago
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Assume there are 10 people in a room, including you. each person in the room must shake hands one time, and only one time, with
Dvinal [7]
You calculate the number of ways that 2 people can be chosen from 10.
The formula:
n! / r! * (n-r)! =
10! / 2! * 8! =
10 * 9 * 8! / 2 * 8! =
10 * 9 / 2 =
45 handshakes

Source:
http://www.1728.org/combinat.htm


4 0
3 years ago
Seattle-Pipes Co. produces pipes to be supplied to a Seattle utility company. The requirement of the utility company is that the
Goshia [24]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Pipe length.

It is known that this variable has a normal distribution and that the distribution parameter varies depending on the process used to manufacture the pipes.

Process A: μ= 200cm δ= 0.5cm

Process B: μ=201cm δ= 1cm

Process C: μ=202cm δ= 1.5cm

Pipes with a length of 200cm or more will be accepted by the utility company (X≥200), but pipes with less than 200cm length will be rejected (X<200)

a. Using Process C, you need to calculate the probability that the pipe will be rejected, symbolically:

P(X<200)

Using the distribution data of process C you have to standardize the value:

P(Z<(200-202)/1.5)= P(Z<-1.33)= 0.09176

b. The requirements change, accepting any pipe between 199 and 202, you have to calculate the probabilities of the pipes being between those lengths using the three process:

Process A:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-200)/0.5)) - P(Z≤(199-200)/0.5))

P(Z≤4) - P(Z≤-2) = 1 - 0.02275 = 0.97725

The probability of the pipe being rejected is 0.02275

Process B:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-201)/1)) - P(Z≤(199-201)/1))

P(Z≤1) - P(Z≤-2) = 0.84134 - 0.02275 = 0.81859

The probability of the pipe being rejected is 1-0.81859= 0.18141

Process C:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-202)/1.5)) - P(Z≤(199-202)/1.5))

P(Z≤0) - P(Z≤-2) = 0.5 - 0.02275 = 0.47725

The probability of the pipe being rejected is 1-0.47725= 0.52275

The pipes manufactured using process A has fewer chances of being rejected.

c.

Process A costs $140

P(X≥200)= 1 - P(X<200)= 1 - P(Z<0)= 1 - 0.5= 0.5

Process B costs $160

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1)= 1 - 0.15866= 0.84134

Process C costs $177

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1.33)= 1 - 0.09176= 0.90824

If they where to make 100 pipes:

Using process A: 100*0.5= 50 pipes will be accepted, so they'll win 50*($200-$140)= $3000

Using process B: 100*0.84134= 84.134≅ 84 pipes will beaccepted, so they'll win 84*($200-$160)= $3360

Using the process C: 100*0.90824= 80.824≅ 90 pipes will be accepted, so they'll win 90*($200-$177)= $2070

As you can see, using process B will maximize the profits.

I hope it helps!

6 0
4 years ago
1/3 x 1/5 in the simplest form
n200080 [17]
1/15 would be the simplest form 3x5=15
3 0
3 years ago
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