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Wittaler [7]
3 years ago
6

Add: 4.15+2.15 8.15 2.5 4.15 1.5

Mathematics
1 answer:
nadezda [96]3 years ago
6 0
4.15
+ 2.15
=6.30
That’s the answer
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For each random variable defined here, describe the set of possible values for the variable, and state whether the variable is d
Alona [7]

Answer:

X is a discrete random variable.

X can take values from 0 to 12:

X\in[0,1,2,3,4,5,6,7,8,9,10,11,12]

Step-by-step explanation:

(a) X = the number of unbroken eggs in a randomly chosen standard egg carton

X is a discrete random variable.

The minimum amount of eggs broken is 0 and the maximum amount of eggs broken is 12 (assuming a dozen egg carton).

Then, X can take values from 0 to 12:

X\in[0,1,2,3,4,5,6,7,8,9,10,11,12]

About the probability ditribution nothing can be said, because there is no information about it (it can be a binomial, uniform or non-standard distribution).

5 0
3 years ago
WILL MARK BRAINLIEST!! Which of the following ordered pairs are y-intercepts? Check all that apply.
Y_Kistochka [10]
Y intercept is where the line meets the Y axis
So the points shd be in (0,y) form.

So (0,0) (0,-7) (0,-0.25) are the y-intercepts in the following.
8 0
3 years ago
Read 2 more answers
Marian Abelt tests video games.She earns $8.125 per hour.Last week she worked 35.50 hours.What was her straight-time pay?
Vlad1618 [11]
Her straight-time pay was $288.44.
7 0
3 years ago
Fill in the blank with a constant, so that the resulting expression can be factored as the product of two linear expressions: 2a
sdas [7]

Answer:

-15

Step-by-step explanation:

We proceed as follows;

In this question, we want to fill in the blank so that we can have the resulting expression expressed as the product of two different linear expressions.

Now, what to do here is that, when we factor the first two expressions, we need the same kind of expression to be present in the second bracket.

Thus, we have;

2a(b-3) + 5b + _

Now, putting -15 will give us the same expression in the first bracket and this gives us the following;

2a(b-3) + 5b-15

2a(b-3) + 5(b-3)

So we can have ; (2a+5)(b-3)

Hence the constant used is -15

8 0
3 years ago
two hundred tickets for the school play were sold. tickets cost $2 for students and $3 for adults. the total amount collected wa
Gre4nikov [31]
A system of equations is good for a problem like this.
Let x be the number of student tickets sold
Let y be the number of adult tickets sold
x + y = 200
2x + 3y = 490
x = 200 - y
2(200 - y) + 3y = 490
400 - 2y + 3y = 490
400 + y = 490
y = 90
The number of adult tickets sold was 90.
x + 90 = 200 --> x = 110
2x + 3(90) = 490 --> 2x + 270 = 490 --> 2x = 220 --> x = 110
The number student tickets sold was 110.
4 0
3 years ago
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