the school is hosting a pet show. there are a total of 110 dogs, cats, and hampsters in the show. if there are twice as many dog
s ad cats, and ten fewer hamosteres than cats,how many cats ate in the show?
2 answers:
Let the number of cats be x cats.
Then number of dogs = 2x and number of hamsters = x - 10 and we can make the equation:-
2x + x + x - 10 = 110 Solve for x:-
4x - 10 = 110
4x = 120
x = 120/4
x = 30 cats (answer)
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