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Mazyrski [523]
2 years ago
10

Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other.

Mathematics
1 answer:
erastovalidia [21]2 years ago
3 0

The Prove that two non-zero vectors are collinear if and only if one vector is a scalar multiple of the other is given below.

<h3>What are the proves?</h3>

1.  To know  collinear vectors:

∧ ⁻a ║ ⁻a

If  ⁻b = ∧ ⁻a

then |⁻b| = |∧ ⁻a|

So one can say that  line ⁻b and ⁻a are  collinear.

2.  If ⁻a and ⁻b  are collinear

Assuming |b| length  is  'μ' times of |⁻a |

Then | 'μ' ⁻a| = | 'μ' ⁻a|

So  ⁻b = 'μ' ⁻a

Learn more about vectors  from

brainly.com/question/25705666

#SPJ1

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2\frac{2}{3} of 2\frac{17}{56} is 6\frac{1}{7}

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Given 2\frac{2}{3} of what number is 6\frac{1}{7}.

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$2\frac{2}{3}=\frac{(2\times3)+2}{3}=\frac{8}{3}

$6\frac{1}{7}=\frac{(6\times7)+1}{3}=\frac{43}{3}

Now, let us take the unknown number be x.

$2\frac{2}{3}\times x=6\frac{1}{7}

$\frac{8}{3}\times x=\frac{43}{7}

Do the cross multiplication.

$ x=\frac{43}{7}\times\frac{3}{8}

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