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Dmitriy789 [7]
3 years ago
14

2 concentric circles have radii 2cm and 3cm respectively, calculate the ratio of their areas​

Mathematics
1 answer:
VikaD [51]3 years ago
6 0

Answer:For the first circle the radius is 2cm and for the second circle the radius is 3cm,by taking the ratio of their areas:

πr^2:πR^2

π cancels out and we are left with only r^2:R^2

r=2cm and R=3cm

Therefore r^2:R^2=2^2:3^2

=4:9

The answer is 4:9

Step-by-step explanation:

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Drag each equation to the correct location on the table.
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Hi! I hope this is correct please inform me if this is incorrect :)

a = 1 will have.

2a + 3 < 9 - 3a.  

2a + 3 > 10 -3a.  

3a - 2a + 1>2.

a = 2 will have

ANY others I did not include in a = 1 :)

Please once again tell me if this is incorrect.

Step-by-step explanation:

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I’ll award you brainliest if you answer This question
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Answer:

$2353 at 12.5% and $7647 at 8.25%

Step-by-step explanation:

I'll say a is the amount he invested in one market, and b is the amount in the other.

a + b = 10000, or b = 10000 - a

multiplying the investments with the percentages and adding them together will give the total earned interest.

(a × 0.125) + (b × 0.0825) = 925

0.125a + 0.0825b = 925

Use substitution to solve for a.

0.125a + 0.0825(10000 - a) = 925

0.125 a + 825 - 0.0825a = 925

0.0425a = 100

a = 2352.94

Use substitution to find b

b = 10000 - 2352.94

b = 7647.06

The questions are to the nearest dollar so round a and b.

$2353 and $7647

6 0
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Jamie rented a canoe while she was on vacation. She paid a flat $85.00 plus $7.50 each day. Her total cost was $130.00. For how
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A carpenter is building a rectangular shed with a fixed perimeter of 54 ft. What are the dimensions of the largest shed that can
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Answer:

the Largest shed dimension is 13.5 ft by 13.5 ft

Largest Area is 182.25 ft²

Step-by-step explanation:

Given that;

Perimeter = 54 ft

P = 2( L + B ) = 54ft

L + B = 54/2

L + B = 27 ft

B = 27 - L ------------Let this be equation 1

Area A = L × B

from equ 1, B = 27 - L

Area A = L × ( 27 - L)

A = 27L - L²

for Maxima or Minima

dA/dL = 0

27 - 2L = 0

27 = 2L

L = 13.5 ft

Now, d²A/dL² = -2 < 0

That is, area is maximum at L = 13.5 using second derivative test

B = 27 - L

we substitute vale of L

B = 27 - 13.5 = 13.5 ft

Therefore the Largest shed dimension = 13.5 ft by 13.5 ft

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3 years ago
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