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3 years ago

Solve the equation. Identify any extraneous solutions

Mathematics

1 answer:

Lelu [443]3 years ago

4 0

Squaring both sides of the given equation: w^2=7w, or w^2-7w=0.

w^2-7w=0 can be factored: w(w-7)=0. Then, w=7 or w=0. Both 0 and 7 are solutions of this equation.

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. Exam scores for a large introductory statistics class follow an approximate normal distribution with an average score of 56 an

Andru [333]

Answer:

0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 56, \sigma = 5, n = 20, s = \frac{5}{\sqrt{20}} = 1.12$

What is the probability that the average score of a random sample of 20 students exceeds 59.5?

This is 1 subtracted by the pvalue of Z when $X = 59.5$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{59.5 - 56}{1.12}$

$Z = 3.1$

$Z = 3.1$ has a pvalue of 0.9990.

So there is a 1-0.9990 = 0.001 = 0.1% probability that the average score of a random sample of 20 students exceeds 59.5.

3 0

3 years ago

Which figure has a greater area? 19 ft 16.4 ft . 15 ft 16.1 ft

Makovka662 [10]

Answer:

green triangle

Step-by-step explanation:

The green triangle has an area of

A = 1/2 bh

A = 1/2 (15) * 19

A =142.5 ft^2

The blue triangle has an area of

A = 1/2 bh

A = 1/2(16.1) (16.4)

A =132.02 ft^2

The green triangle has a greater area

7 0

3 years ago

How much is 2.1x 82

hram777 [196]

2.1 x 82 =

172.2

I hope this answer was helpful! :)

8 0

3 years ago

Read 2 more answers

A see-saw is 25 feet long with a fulcrum in the middle of the board. If a 60 lb. child sits three feet from the fulcrum, what is

My name is Ann [436]

Answer:

14.4 lb

Step-by-step explanation:

In a see-saw in equilibrium, the torque generated by one side needs to be the same generated in the other side. The torque is calculated by the product between the mass and the distance to the center of the see-saw.

The torque generated by the child is:

T1 = 60 * 3 = 180 lb*feet

So, the torque generated by the weight needs to be higher than T1 in order to lift the child.

The lowest mass is calculated when the mass is in the maximum distance, that is, 12.5 feet from the center.

So, we have that:

T2 = 180 = mass * 12.5

mass = 180/12.5 = 14.4 lb

So the lowest weight is 14.4 lb

4 0

3 years ago

Find the area of a regular octagon with

sattari [20]

Answer:

482.8 cm

Step-by-step explanation:

A=2(1+sqrt2)a^2=2·(1+squrt2)·10^2=482.84271

4 0

2 years ago