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3 years ago

MARK AS BRAINLIEST!!

Mathematics

2 answers:

Nimfa-mama [501]3 years ago

8 0

Answer: There is 58.3% of students that are not convinced.

Step-by-step explanation:

Since we have given that

Number of schools = 300

Number of schools that are convinced to sell their products = 125

Number of schools that are not convinced to sell their products = 300 - 125 = 175

Percentage of schools that are not convinced is given by

(175 ÷ 300) × 100

= 175 ÷ 3

= 58.3 %

Hence, there is 58.3% of students that are not convinced.

Kobotan [32]3 years ago

4 0

Answer:

58.3%

Step-by-step explanation:

125/300 people decided to buy their product but 175 didn't to get the answer for the problem you just divide 175 by 300 which gets you 0.58333... in which you move the decimal place two to the right which gives you 58.3 then that is your percent 55.3%

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prohojiy [21]

Answer:

a) 52 ounces

b) 24 pints

Step-by-step explanation:

A:There are 16 ounces in a pound. Thus, you can simply multiply 3.25 by 16 to get 52.

B: Simply multiply 0.15 * 20 to get 3. Then multiply 3 by 8 to get 24.(8 pints per gallon)

Hope it helps <3

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3 years ago

Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – x – 7 = 0

Tanzania [10]

2x-x-7=0

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3 years ago

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mezya [45]

1/2 = 4/8

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3 years ago

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WHAT IS 24 DIVIDED BY 48 WITH WORK PLEASE

kotegsom [21]

So,

$\frac{24}{48}$

Write in prime factored form.
$\frac{2*2*2*3}{2*2*2*2*3}$

Cross-cancel
$\frac{1}{2}$

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4 years ago

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Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently

garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

$\small \sum_{i = 1}^{k} L_i= 2\pi$

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

$\small \sum_{i = 1}^{k} C_i.l = 2\pi$

where C(i) is a constant coefficient obviously between 0 and 1.

$\small \sum_{i = 1}^{k} C_i= 2\pi/l$

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

$\small L_{Exp} = \frac{2\pi}{k}$

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3 years ago