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2 years ago

Find the area of quadrilateral ABCD. [Hint: the diagonal divides the quadrilateral into two triangles.]

Mathematics

1 answer:

Rasek [7]2 years ago

7 0

The area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

<h3>What is quadrilateral?</h3>

It is defined as the four-sided polygon in geometry having four edges and four corners. It has one pair of opposite congruent angles and the diagonals of a kite are perpendicular.

We have a quadrilateral shown in the picture.

The diagonal divides the quadrilateral into two triangles

The area of the quadrilateral = area of the triangle ADC + area of the

triangle ADB

= (1/2)3.42×4.39 + (1/2)5.44×3.42

= 7.5069 + 9.3024

= 16.80 square units

Thus, the area of the quadrilateral is 16.80 square units if the diagonal divides the quadrilateral into two triangles.

Learn more about the quadrilateral here:

brainly.com/question/6321910

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3 years ago

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blagie [28]

Answer:

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3 years ago

Two solutions of the equation Ax+By = 1 are (2, -1) and (-3,-2). Find A and B.

kati45 [8]

Answer:

Substitute in the values of both given coordinates & form 2 equations:

$\left \{ {{A(2)+B(-1)=1} \atop {A(-3)+B(-2)=1}} \right. \\\\=\left \{ {{2A-B=1} \atop {-3A-2B=1}} \right.$

Find the value of B from the equation 2A - B = 1:

$2A-B=1\\-B=1-2A\\B=2A-1$

Substitute in the B-value to the other equation:

$-3A-2B=1\\-3A-2(2A-1)=1\\-3A-4A+2=1\\-7A=1-2\\-7A=-1\\A=\frac{-1}{-7} =\frac{1}{7}$

Find the B-value using the equation from before:

$B=2A-1=2(\frac{1}{7})-1=\frac{2}{7} -\frac{7}{7} =-\frac{5}{7}$

Therefore the equation Ax + By = 1 would equal:

$\frac{1}{7} x-\frac{5}{7} y=1$

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3 years ago

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nirvana33 [79]

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago