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ArbitrLikvidat [17]
3 years ago
10

Graph the equation y-1=-3(x-3)

Mathematics
2 answers:
Oksana_A [137]3 years ago
7 0

Answer:

Step-by-step explanation:

Image below

trapecia [35]3 years ago
5 0

Answer:

y= -3x +10

the y-intercept is at 10 and then go 3 down one to the right

Step-by-step explanation:

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8x+3y=4 <br> -7x+5y=-34 <br><br> Elimination using multiplication
irga5000 [103]

Answer:

x= 2    and y = -4

Step-by-step explanation:

8x + 3y = 4 ---------------------------------(1)

-7x + 5y = -34 -----------------------------(2)

Multiply through equation (1) by 5 and multiply through equation(2) by 3

40x + 15y = 20 ----------------------------(3)

-21x + 15y =-102----------------------------(4)

Subtract equation (4) from equation (3)

61x = 122

Divide both-side of the equation by 61

61x/61 = 122/61

(At the left-hand side of the equation 61 will cancel-out 61 leaving us with just x, while at the left-hand side of the equation 122 will be divided by 61)

x = 122/61

x=2

Substitute x= 2 into equation (1)

8x + 3y = 4

8(2) + 3y = 4

16 + 3y = 4

Subtract 16 from both-side of the equation

16-16 + 3y = 4-16

3y = -12

Divide both-side of the equation by 3

3y/3 = -12/3

y = -4

x= 2    and y = -4

4 0
3 years ago
Read 2 more answers
The lengths of sides of a triangle are (3x+2), (2x+5), and 4x. Terrel correctly added the lengths of the three sides to find the
Charra [1.4K]
So permiter=masure of all sides added together
so sides are(3x+2), (2x+5), and (4x)
so (3x+2)+(2x+5)+(4x)
use associative property
a+(b+c)=(a+b)+c so

(3x+2)+(2x+5)+(4x)=3x+2+2x+5+4x
group like terms becasue can move numbers around
(3x+2x+4x)+(2+5)
add like terms
(9x)+(7)
9x+7
he will use 9x+7=perimiter





7 0
2 years ago
Read 2 more answers
15 pts the cost of 5 cartons of fresh ice cream is $8.75 what is the cost of 11 such cartons
Morgarella [4.7K]

Answer:

C ($19.25)

Step-by-step explanation:

First, find how much 1 carton costs, which is $8.75 divided by 5, which is $1.75. So, to find how much 11 cartons cost, we just multiply by 11 to get [tex]\boxed{\$19.25}[\tex]

5 0
2 years ago
Read 2 more answers
A basin is filled by two pipes in 12 minutes and 16 minutes respectively. Due to the obstruction of water flow after the two pip
olasank [31]

Answer:

The time duration of the two pipes restricted flow before the flow became normal is 4.5 minutes

Step-by-step explanation:

The given information are;

The time duration for the volume, V, of the basin to be filled by one of the pipe, A, = 12 minutes

The time duration for the volume, V, of the basin to be filled by the other pipe, B, = 16 minutes

Therefore, the flow rate of pipe A = V/12

The flow rate of pipe B = V/16

Due to the restriction, we have;

The proportion of its carrying capacity the first pipe, A, carries = 7/8 of the carrying capacity

The proportion of its carrying capacity the second pipe, B, carries = 5/6 of the carrying capacity

Whereby the tank is filled 3 minutes after the restriction is removed, we have;

\dfrac{7}{8} \times \dfrac{V}{12} \times t + \dfrac{5}{6} \times \dfrac{V}{16} \times t +  \dfrac{V}{12} \times 3 + \dfrac{V}{16} \times 3 = V

Simplifying gives;

\dfrac{(2\cdot t +7) \cdot V}{16}  = V

2·t + 7 = 16

t = (16 - 7)/2 = 4.5 minutes

Therefore, it took 4.5 seconds of the restricted flow before the the flow of water in the two pipes became normal

7 0
3 years ago
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tia_tia [17]

Answer:

c the 1st

a the 2nd

b the 3rd

c the 4th

6 0
3 years ago
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