First box = 14 pounds
Second box = 2x = 28 pounds
Third Box = x+2= 16 pounds
Fourth box = x/2 = 7 pounds
<u>Step-by-step explanation:</u>
Here we have , Sixty-five pounds of candy was divided into four different boxes. The second box contained twice the amount of the first box. The third box contained two more pounds than the first box. The last box contained one-fourth the amount in the second box. We need to find How much candy was in each box. Let's find out:
We have a total of 65 pounds of candy ! Let in first box we have x pounds so , second box contained twice the amount of the first box i.e.
⇒ 
The third box contained two more pounds than the first box i.e.
⇒ 
The last box contained one-fourth the amount in the second box i.e.
⇒ 
Therefore , Sum of pounds of candy are :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , Candy in each box is :
First box = 14 pounds
Second box = 2x = 28 pounds
Third Box = x+2= 16 pounds
Fourth box = x/2 = 7 pounds
Answer:
4/3 or 1 1/3 brownie
Step-by-step explanation:
Answer:
The answer would be Equation B:
x2 - 8x + 41
Step-by-step explanation:
Answer:
x = 27.57 in to the nearest hundredth.
Step-by-step explanation:
The longer diagonal is opposite the obtuse angle.
Also as it is a rhombus all sides = 14 in.
Use the Cosine Rule:
x^2 = 14^2 + 14^2 - 2*14^2 cos 160
x^2 = 760.36
x = sqrt 760.36
x = 27.57 in.
<span>The factors of 60 are 60, 30, 20, 15, 12, 10, 6, 5, 4, 3, 2, 1.The factors of 75 are 75, 25, 15, 5, 3, 1.<span>The common factors of 60 and 75 are 15, 5, 3, 1, intersecting the two sets above.</span><span>In the intersection factors of 60 ∩ factors of 75 the greatest element is 15.</span><span>Therefore, the greatest common factor of 60 and 75 is 15.
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