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MAVERICK [17]
2 years ago
5

Which equation would match the table the most?? pls help ☠️☠️

Mathematics
1 answer:
AVprozaik [17]2 years ago
3 0
X-4y=13 would match the best
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5.00 divided by .04 with work please
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The answer for this question is 125. (Sorry for not showing any work, very complicated to show and explain)
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3 years ago
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In the triangle ABC, point M is the midpoint of AB and point G in the medicander. It is given that CG = 15 cm. Find how much GM
svp [43]

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

CG = \frac{2}{3} CM \\

15 =  \frac{2}{3} CM \\

\frac{2}{3} CM = 15 \\

Multiply sides by 3

3 \times  \frac{2}{3} CM = 3 \times 15 \\

2CM = 45

Divide sides by 2

\frac{2CM}{2}  =  \frac{45}{2}  \\

CM = 22.5

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

CM = CG + GM

22. = 15 + GM

GM + 15 = 22.5

Subtract sides 15

GM + 15 - 15 = 22.5 - 15

GM = 7.5

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5 0
3 years ago
I need help please giving brainliest!
Alchen [17]

Answer:

acute: D and E

obtuse: A and F

right: B

straight: C

Step-by-step explanation:

7 0
4 years ago
Elimination Method: 6x - 4y = -24 and 4x + 5y = -2
nirvana33 [79]

Answer:

(-2;-6)

Step-by-step explanation:

First of all, let's rewrite the first one after dividing both sides by 2.

\left \{ {{3x-2y=-12\atop {4x+5y=-2}} \right.

Now, let's pick one you want to eliminate.

<u>Eliminating x:</u> Let's multiply the first one by 4, the second by 3, and subtract one from the other. Rest is simply solving an equation in one variable

4I-3II : 12x-8y-12x+15y = -48 - (-6)\\7y = -42 \rightarrow y= -6

<u>Eliminating y:</u> Let's multiply the first by 5, the second by 2, and add them together. Rest is simply solving an equation in one variable

5I+2II: 15x -10y +8x +10y = -60 +4\\23x = -56 \rightarrow x=-2

4 0
3 years ago
Are these triangles similar?
Fiesta28 [93]

Answer:

B. Yes, by the AA Similarity Postulate

Step-by-step explanation:

This triangles are both similar based on the AA Similarity Postulate. We know that all angles are equal because...

m∠ABE = m∠CBD = 42° (because they are veridical/opposite angels)

m∠AEB = 180° - m∠ABE - m∠EAB = 180° - 42° - 53° = 85°

Then from here we know that

m∠BDC = 180° - 85° - m∠CBD

m∠BDC = 95° - 42°

m∠BDC = 53°

From here we see that they are similar because of the AA Similarity Postulate, since

m∠ABE = m∠CBD = 42°

m∠BDC = m∠EAB = 53°

m∠AEB = m∠BCD = 85°

5 0
3 years ago
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