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2 years ago

Equivalent fractions to 7/4

1 answer:

7 0

Equivalents fractions for 7/4:
7/4, 14/8, 21/12, 28/16, 35/20, 42/24, 49/28, 56/32, 63/36, 70/40, and so on ...

Example:
7/4 * 2/2 = 14/8
7/4 * 3/3 = 21/12
7/4 * 4/4 = 28/16
7/4 * 5/5 = 35/20
7/4 * 6/6 = 42/24 and so on.......

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Refer to the previous exercise. The researchers wanted a sufficiently large sample to be able to estimate the probability of pre

Maru [420]

Answer:

The large sample n = 117.07

Step-by-step explanation:

Step(i):-

Given that the estimate error (M.E) = 0.08

The proportion (p) = 0.75

q =1-p = 1- 0.75 =0.25

Level of significance = 0.05

Z₀.₀₅ = 1.96≅ 2

Step(ii):-

The Marginal error is determined by

M.E = $\frac{Z_{0.05} \sqrt{p(1-p)} }{\sqrt{n} }$

$0.08 = \frac{2 X \sqrt{0.75(1-0.75)} }{\sqrt{n} }$

Cross multiplication , we get

$\sqrt{n} = \frac{2 X \sqrt{0.75(1-0.75)} }{0.08 }$

√n = $\frac{2 X0.4330}{0.08} = 10.825$

squaring on both sides , we get

n = 117.07

Final answer:-

The large sample n = 117.07

6 0

2 years ago

The librarian purchased 22 copies of a best-selling book for $385.66.

kow [346]

Answer:

$17.53

Step-by-step explanation:

$385.66 divided by 22 equals the how much each book cost

5 0

3 years ago

Find f(-2) if f(x) = x + x + 7. f(-2) =

Lynna [10]

Answer:

f(-2) = 9

Step-by-step explanation:

Given that,

f(x) = x² + x + 7

We need to find the value of f(-2).

Put x = -2 in the given function.

f(-2) = (-2)² + (-2) + 7

= 4-2+7

= 9

Hence, the value of f(-2) is equal to 9.

3 0

2 years ago

(10 points) Consider the initial value problem y′+3y=9t,y(0)=7. Take the Laplace transform of both sides of the given differenti

Rashid [163]

Answer:

The solution

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3 t}$

Step-by-step explanation:

Explanation:-

Consider the initial value problem y′+3 y=9 t,y(0)=7

Step(i):-

Given differential problem

y′+3 y=9 t

Take the Laplace transform of both sides of the differential equation

L( y′+3 y) = L(9 t)

Using Formula Transform of derivatives

L(y¹(t)) = s y⁻(s)-y(0)

By using Laplace transform formula

$L(t) = \frac{1}{S^{2} }$

Step(ii):-

Given

L( y′(t)) + 3 L (y(t)) = 9 L( t)

$s y^{-} (s) - y(0) + 3y^{-}(s) = \frac{9}{s^{2} }$

$s y^{-} (s) - 7 + 3y^{-}(s) = \frac{9}{s^{2} }$

Taking common y⁻(s) and simplification, we get

$( s + 3)y^{-}(s) = \frac{9}{s^{2} }+7$

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

Step(iii):-

By using partial fractions , we get

$\frac{9}{s^{2} (s+3} = \frac{A}{s} + \frac{B}{s^{2} } + \frac{C}{s+3}$

$\frac{9}{s^{2} (s+3} = \frac{As(s+3)+B(s+3)+Cs^{2} }{s^{2} (s+3)}$

On simplification we get

9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Put s =0 in equation(i)

9 = B(0+3)

B = 9/3 = 3

Put s = -3 in equation(i)

9 = C(-3)²

C = 1

Given Equation 9 = A s(s+3) +B(s+3) +C(s²) ...(i)

Comparing 'S²' coefficient on both sides, we get

9 = A s²+3 A s +B(s)+3 B +C(s²)

0 = A + C

put C=1 , becomes A = -1

$\frac{9}{s^{2} (s+3} = \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}$

Step(iv):-

$y^{-}(s) = \frac{9}{s^{2} (s+3}+\frac{7}{s+3}$

$y^{-}(s) =9( \frac{-1}{s} + \frac{3}{s^{2} } + \frac{1}{s+3}) + \frac{7}{s+3}$

Applying inverse Laplace transform on both sides

$L^{-1} (y^{-}(s) ) =L^{-1} (9( \frac{-1}{s}) + L^{-1} (\frac{3}{s^{2} }) + L^{-1} (\frac{1}{s+3}) )+ L^{-1} (\frac{7}{s+3})$

By using inverse Laplace transform

$L^{-1} (\frac{1}{s} ) =1$

$L^{-1} (\frac{1}{s^{2} } ) = \frac{t}{1!}$

$L^{-1} (\frac{1}{s+a} ) =e^{-at}$

Final answer:-

Now the solution , we get

$Y (s) = 9( -1 +3 t + e^{-3 t} ) + 7 e ^{-3t}$

5 0

2 years ago

1. 1.4(x−1.6)=1.6(x−1.4) solve 2. 1.4(x−1.6)=1.6(1.4−x) solve

Bezzdna [24]

1.
$1.4( x - 1.6) = 1.6(x - 1.4) \\ 1.4x - 2 .24 = 1.6x - 2.24 \\ 0.2x = 0 \\ x = 0$
2.
$1.4( x - 1.6) = 1.6(1.4 - x) \\ 1.4x - 2 .24 = 2.24 - 1.6x \\ 3x = 4.48 \\ x = 1.4933333$

5 0

3 years ago