First, solve for the volume of the ball bearings by the equation,
V = πd³ / 6
Substituting the value of diameter given,
V = π(1 cm)³ / 6 = π/6 cm³ = 0.5236 cm³
Divide the amount of material given by this volume,
n = 5.24 cm³ / <span>0.5236 cm³ = 10
Therefore, there are 10 ball bearings that may be formed.</span>
Answer:
B: 340
Step-by-step explanation:
We are told that her walls are 8 ft high.
Now, Two walls are 10 feet wide. Thus, area of the first two walls will be;
A1 = 2 × (10 × 8) = 160 sq.ft
Also, the other 2 walls are 15 feet wide.
Thus, Area of other two walls will be;
A2 = 2 × (15 × 8) = 240 sq.ft
We are told that the combined area of the 1 window and the 1 door in her room in 60 square feet.
This means that we will subtract 60 Sq.ft from the sum of the area of the 2 walls earlier calculated to get the total area to be painted.
Thus;
Area to be painted = 160 + 240 - 60 = 340 Sq.ft
413,125 rounded to the nearest hundred thousand is 400,000
X-intercept is 8
Y-intercept is 3
X= -2 and x= 2 are the answers
