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Degger [83]
3 years ago
9

Help me find the value of x!!!

Mathematics
1 answer:
Katen [24]3 years ago
7 0

The value of x is B. 8.

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which of the following polynomials has a graph with odd symmetry? a. 7x^4+13x^3-11 b. 5x^7+4x^6+3x^5+x c.13x^5 -1/2x^3+7x+3 d. 8
agasfer [191]

Answer: 45x3x345!3

Step-by-step explanation:

you multiply all numbers then you divide by all the numbers there and there’s your answer

6 0
2 years ago
Read 2 more answers
Which number line models the solution set of -2x + 7 > 17?Pls do 2 answers for good measures (and brainliest)
Sidana [21]

Step-by-step explanation:

We can immediately eliminate answers B and C because we have >, meaning that the circle on the number line has to be open.

-2x+7>17

subtract 7 on both sides

-2x>10

divide by -2. remember that dividing by a negative flips the greater than or less than sign.

x<-5

the answer is D

4 0
3 years ago
Whats the Area? how do i find it? In these specific questions?
just olya [345]
The formula for finding the area of a square is:
{s}^{2}

The formula for finding the area of a triangle is:
\frac{1}{2} bh

So for the square the area would be:
{2x}^{2} \times  {2x}^{2}  =  {4x}^{2}

The area for the triangle would be:

\frac{1}{2}  {2c}^{3}  \times  4c =  {4c}^{2}
7 0
3 years ago
The diagonals of a quadrilateral QRST intersect at P(-1,3). QRST has vertices at Q(3,6) and R(-4,5). What must be the coordinate
erica [24]

S = (-5,0)

T = (2,1)

Step-by-step explanation:

Step 1 :

Given

Q = (3,6) and R = (-4,5). P = (-1,3)

Let S be (a,b) and T be (c,d)

The diagonals of a parallelogram bisect each other. so in order to ensure that QRST is a parallelogram, P must be the mid point of the diagonals QS and RT.

Step 2 :

P is the midpoint  of QS

So we have (3+a) ÷ 2 =  -1  and (6 + b) ÷ 2 = 3

=> 3 + a = -2    and 6 + b = 6

=> a = -5  and b =0

So S should be (-5,0)

Step 3 :

P is the midpoint  of RT

So we have (-4+c) ÷ 2 =  -1  and (5 + d) ÷ 2 = 3

=> -4+ c = -2    and 5 + d = 6

=> c = 2  and d =1

So T should be (2,1)

Step 4 :

Answer :

S = (-5,0)

T = (2,1)

6 0
3 years ago
Write four different expressions for the perimeter of a pentagon whose sides are all s-2 units long?
Masteriza [31]

Hey there!

1. 5(s-2) This is because s-2 is the length of each side, and there are 5 sides in a pentagon all of that length, so multiplying it by 5 like this shows its perimeter.

2. 5s-10 This can be found by distributing the first equation, multiplying both s and -2 by 5.

3. (s-2) + (s-2) + (s-2) + (s-2) + (s-2) Each grouping in the parenthesis represents each of the 5 sides, so adding them all together will get you the perimeter.

4. 5(s) + 5(-2) This one is most like the first one, except it's a little more spread out. Multiply the term s by the 5 sides in one grouping, and the integer -2 by 5 in the other.

Hope this helps!

4 0
3 years ago
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