All categories

2 years ago

Species with homologous structures most likely:

Biology

2 answers:

nikitadnepr [17]2 years ago

7 0

Species with more likely homologous structures share a common ancestor.

D. share a common ancestor.

<h3>What are example homologous structures?</h3>

The most correct definition for homology would be: They are structures of individuals, of different species or not, that were inherited from a common ancestor. The human arm is homologous to the horse's front leg. The bat's wing is homologous to the whale fin.

With this information, we can conclude that homologous have same embryological origin of structures from different organisms, and these structures may or may not have the same function

Learn more about homologous structures in brainly.com/question/7904813

#SPJ1

Natali5045456 [20]2 years ago

4 0

Groups with homologous characters share a common ancestor. These characters have the same embryological development, although their function might vary. Option D. share a common ancestor.

<h3>What is a homologous character?</h3>

Homologous characters are structures with the same basic elements.

Their position in the body and the relations with adjacent structures are also the same in different organisms, and they even share the same embryological development.

These structures might show variations between the organisms exhibiting them. Variations might be related to their function and to the environment in which the organism lives. The function they accomplish is not necessarily the same in all the organisms involved.

These homologous characters are present in organisms related that share a common ancestor.

For example, whales, humans, and cats all have the same bones in the same order, but they matured differently in later embryological development.

The correct option is then option D. Species with homologous structures most likely share a common ancestor.

You can learn more about homologous characters at

brainly.com/question/4800917

#SPJ1

You might be interested in

The more early abortions a woman has, the more likely it is that she will become sterile. true false

sergejj [24]

False?, it more or less goes on the amounts of abortions the more you get the more chances you'll become infertile,

6 0

4 years ago

Identify the genotype for each numbered item.

serious [3.7K]

Answer:

there should be a picture or something

Explanation:

8 0

3 years ago

Read 2 more answers

If the nerve cell connecting the spinal cord to your feet is 1.4 m long, and the nerve impulse speed is 25 m/s, how many seconds

liubo4ka [24]

Answer:

Time taken by the nerve signal for travelling this distance $= 0.056$ seconds

Explanation:

Given,

The length of nerve cell connecting the spinal cord to the feet $= 1.4 m$

Speed of nerve impulse $25\frac{m}{s}$

Time taken for the nerve signal to travel this distance is equal to the total " length of nerve cell connecting the spinal cord to the feet" divided by "speed of nerve impulse"

Substituting the given values in above equation, we get -

$\frac{1.4}{25}$

$= 0.056$ seconds.

Thus , time taken by the nerve signal for travelling this distance $= 0.056$ seconds

3 0

4 years ago

When a conditional and its converse are true, you can combine them as a true ____.

lions [1.4K]

Answer – B. Bioconditional
When a conditional and its converse are true, you can combine them as a true biconditional. A biconditional statement is said to be true when both parts have the same truth value, i.e. both the conditional and its converse are true.

5 0

3 years ago

Read 2 more answers

PLEASE solve number 1 and 2 because i don’t get it , don’t mind my answers

Readme [11.4K]

Answer:

1) RNA strand = UCA GCA AAU

2) Amino acids: Asparagine Arginine Stop

(ASN) (ARG) (STOP)

Explanation:

Some theory that you need to know to answer the question:

Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named anticodon. The other site couples with an amino acid through the action of the aminoacyl-tRNA synthase enzyme. The whole complex, amino acid + enzyme + tRNA is named aminoacyl-tRNA. Considering that there are twenty amino acids available, there are also twenty complexes of aminoacyl-tRNA, one for each amino acid.

tRNA allows amino acids to align according to the nucleotidic sequence in the mRNA molecule.

Once the new amino acid joins the growing peptidic chain, the binding between the amino acid and the tRNA molecule breaks. The tRNA is now free to join another amino acid and repeat the cycle.

Now, to fill in the boxes, you need to pay attention to two things:

• Anticodon: In this box, you need to place the sequence of bases that pairs with the mRNA codon.

• Amino Acid: In this box, you need to place the amino acid that is codified by the mRNA codon.

For instance, let us say that the codon of mRNA is CUC. The anticodon for this sequence is GAG (because guanine joins cytosine and adenine joins uracyl).

The amino acid places on the 3´extreme of the tRNA molecule will be the one that is codified by the codon, NOT the anticodon. So, as the codon is CUC, the amino acid will be Leucine, Leu. Do not use the anticodon GAG to fill these boxes. Remember that tRNA is translating information carried by the mRNA, so we need to use this information to grow the protein.

Strand of DNI → AGT CGT TTA

Each of these letters are bases → Adenine, A - Guanine, G - Thymine, T - Cytocine, C
Each of these three-lettered groups are codons.

So, we need to pair these bases, knowing that:

Adenine (A) and guanine (G) derive from purines, while Thymine (T) Uracile (U), and Cytosine (C) derive from Pyrimidines.

In the DNA molecule, Adenine (Purine) always pairs with Timine (Pyrimidine), while Guanine (Purin) forms pairs with Cytosine.

In the RNA molecule, Adenine is paired with Uracil, U. So, whenever there is an Adenine in the DNI strand, it pairs with Uracil of RNA strand. If there is a Thymine in the DNI strand, it pairs Adenine of the RNA strand. And, as always, Guanine pairs with Cytosine.

A ⇒ U
T ⇒ A
G ⇔ C

Knowing how to pair bases, we can fill the RNA molecule boxes.

Strand of DNI → AGT CGT TTA
Strand of RNA → UCA GCA AAU

A ⇒ U C ⇒ G T ⇒ A

G ⇒ C G ⇒ C T ⇒ A

T ⇒ A T ⇒ A A ⇒ U

Now we need to translate these new codons of mRNA to amino acids.

To fill the boxes you should have a genetic code chart to see the codons that codify for each amino acid.

Codon: AAU CGA UAG

Amino acids: Asparagine Arginine Stop

(ASN) (ARG) (STOP)

The new protein is synthesized from the amino terminus to the carboxy terminus of the mRNA molecule. The added amino acids to the chain are coded by a codon formed by three bases in the mRNA. mARNs also have a start and end codon that are the signals of the synthesis initiation and finish. When the ribosome reaches a stop codon, protein synthesis is over.

8 0

3 years ago