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jek_recluse [69]
2 years ago
11

Let x be normal distribution with mean 70 and standard deviation 2. given the following probability, p (x < a) = 0.9147, find

the value a.
Mathematics
1 answer:
lapo4ka [179]2 years ago
6 0

The value of a is 72.74.

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

The mean \rm \mu of the distribution is 70

Standard deviation \rm \sigma  is 2

p( x<a) = 0.9147

a = ?

From Z table

For p ( p < 0.9147) , z = 1.37

\rm Z = \dfrac { X - \mu}{ \sigma}

\rm \rm 1.37 = \dfrac { a - 70}{ 2}

a = 70+ 2*1.37

a = 72.74

Therefore the value of a is 72.74.

To know more about Probability

brainly.com/question/11234923

#SPJ1

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We roll two fair 6-sided dice. Each one of the 36 possible outcomes is assumed to be equally likely. (a) Find the probability th
Verizon [17]

Answer:

a) There is a 16.6% probability that doubles were rolled.

b) Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

c) There is a 30.55% probability that at least one die is a 1.

Step-by-step explanation:

The probability formula is the number of desired outcomes divided by the number of total outcomes.

(a) Find the probability that doubles were rolled. (i.e. the two outcomes are equal)

There are six desired outcomes: (1,1), (2,2), (3,3), (4,4), (5,5), (6,6)

There are 36 total outcomes. So:

P = \frac{6}{36} = 0.166

There is a 16.6% probability that doubles were rolled.

(b) Given that the roll resulted in a sum of 6 or less, find the conditional probability that doubles were rolled.

The following rolls result in a sum of 5 or less:

(1,1), (1,2), (1,3), (1,4), (1,5), (2,1), (2,2), (2,3), (2,4), (3,1), (3,2), (3,3), (4,1), (4,2), (5,1)

So, there are 15 total outcomes.

3 of them are doubled: (1,1), (2,2), (3,3). So

P = \frac{3}{15} = 0.2

Given that the roll resulted in a sum of 6 or less, there is a 20% probability that doubles were rolled.

(c) Find the probability that at least one die is a 1

The following outcomes have at least one die that is 1:

(1,1), (1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(3,1),(4,1),(5,1),(6,1)

So, there are 11 desired outcomes out of 36.

P = \frac{11}{36} = 0.3055

There is a 30.55% probability that at least one die is a 1.

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Paladinen [302]

Answer:

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<u><em>Explanation:-</em></u>

Given that the point ( 8,-7) and  m = \frac{-3}{4}

Equation of the straight line passing through the point (x₁, y₁) and having slope 'm'

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