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jek_recluse [69]
2 years ago
11

Let x be normal distribution with mean 70 and standard deviation 2. given the following probability, p (x < a) = 0.9147, find

the value a.
Mathematics
1 answer:
lapo4ka [179]2 years ago
6 0

The value of a is 72.74.

<h3>What is Probability ?</h3>

Probability is the study of likeliness of an event to happen.

It is given that

The mean \rm \mu of the distribution is 70

Standard deviation \rm \sigma  is 2

p( x<a) = 0.9147

a = ?

From Z table

For p ( p < 0.9147) , z = 1.37

\rm Z = \dfrac { X - \mu}{ \sigma}

\rm \rm 1.37 = \dfrac { a - 70}{ 2}

a = 70+ 2*1.37

a = 72.74

Therefore the value of a is 72.74.

To know more about Probability

brainly.com/question/11234923

#SPJ1

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Answer:

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General Formulas and Concepts:

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  3. Exponents
  4. Multiplication
  5. Division
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  • Left to Right<u> </u>

<u>Algebra I</u>

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  • Terms/Coefficients
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<u>Calculus</u>

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Derivative Notation

Basic Power Rule:

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Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \frac{3}{2x^2}<u />

\displaystyle \text{Point} \ (1, \frac{3}{2})

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Rewrite]:                                            \displaystyle y = \frac{3}{2}x^{-2}
  2. Basic Power Rule:                                                                                             \displaystyle y' = -2 \cdot \frac{3}{2}x^{-2 - 1}
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  4. Rewrite [Exponential Rule - Rewrite]:                                                              \displaystyle y' = \frac{-3}{x^3}

<u>Step 3: Solve</u>

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Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

6 0
3 years ago
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