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3 years ago

Pls help with this and show work on piece of paper

Mathematics

2 answers:

Sunny_sXe [5.5K]3 years ago

7 0

2 because 12x3=36 and you couldn’t ride that many bc u wouldn’t have enough $$$ so you have to ride two

Lapatulllka [165]3 years ago

5 0

Answer:

????

i dont know

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2 x - 5 + 7 y - 3 = 9 x - 1 - y -8 Solve For X AND Y (SHOW WORK PLEASE)

Maru [420]

Answer:

$\large\boxed{\sf x = \frac{8y+1}{7} }$

$\large\boxed{\sf x = \frac{7x-1}{8} }$

Group the Variable's:

2 x - 5 + 7 y - 3 = 9 x - 1 - y -8

2x -9x + 7y +y = -1 -8 +5 + 3

-7x + 8y = -1

From this find x and y

For X

-7x + 8y = -1

-7x = -1 -8y

7x = 8y + 1

x = (8y +1)/7

For Y

-7x + 8y = -1

8y = -1 +7x

y = (7x -1)/8

3 0

2 years ago

Read 2 more answers

A random sample of 10 shipments of stick-on labels showed the following order sizes.10,520 56,910 52,454 17,902 25,914 56,607 21

sammy [17]

Answer:

Confidence Interval: (21596,46428)

Step-by-step explanation:

We are given the following data set:

10520, 56910, 52454, 17902, 25914, 56607, 21861, 25039, 25983, 46929

Formula:

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

$Mean =\displaystyle\frac{340119}{10} = 34011.9$

Sum of squares of differences = 551869365.6 + 524322983.6 + 340111052.4 + 259528878 + 65575984.41 + 510538544 + 147644370.8 + 80512934.41 + 64463235.21 + 166851472.4 = 2711418821

$S.D = \sqrt{\frac{2711418821}{9}} = 17357.09$

Confidence interval:

$\mu \pm t_{critical}\frac{\sigma}{\sqrt{n}}$

Putting the values, we get,

$t_{critical}\text{ at degree of freedom 9 and}~\alpha_{0.05} = \pm 2.2621$

$34011.9 \pm 2.2621(\frac{17357.09}{\sqrt{10}} ) = 34011.9 \pm 12416.20 = (21595.7,46428.1) \approx (21596,46428)$

7 0

3 years ago

What is the fraction of 2.6

Solnce55 [7]

2 3/5 or 2 6/10 is the answer

6 0

2 years ago

Read 2 more answers

Use the drop-down menus to complete the statements about factoring 14x2 + 6x – 7x – 3 by grouping. The GCF of the group (14x2 –

Yuliya22 [10]

14 x² + 6 x - 7 x - 3 =
= ( 14 x² - 7 x ) + ( 6 x - 3 ) =
= 7 x ( 2 x - 1 ) + 3 ( 2 x - 1 ) =
= ( 2 x - 1 ) ( 7 x + 3 )
Answer:
1. GCF of the group ( 6 x - 3 ) is 3.
2. The common binomial factor is 2 x - 1.
3. The factored expression is: ( 2 x - 1 ) ( 7 x + 3 ).

8 0

3 years ago

Read 2 more answers

Five men and 5 women are ranked according to their scores on an examination. Assume that no two scores are alike and all possibl

serg [7]

Answer:

P(X=i) where i = 1,2,3,4,5,6,7,8,9,10 = 1/2, 5/18, 5/36, 5/84, 5/252, 1/252, 0, 0, 0, 0.

Step-by-step explanation:

X denotes the highest ranking achieved by the woman.

When X=1, the top ranked person is a female.

When X=2, the first person is a male and the second ranked person is a female.

Similarly, when X=3, the first two ranked persons are male and the third one is a female.

When X=4, the first three persons are male and the fourth one is a female.

When X=5, the first four persons are males and the fifth person is a female.

When X=6, the first five people are males and the sixth person is a female. The rest of the four people are also females since there are only five men in a sample space.

The probability for X=7, 8, 9, 10 is zero because there are only five men who can achieve the first five positions and the last highest rank that can be achieved by a woman is 6.

To compute the probabilities, we will use the formula:

No. of ways a female can be ranked X/Total number of ways to rank 10 people

Note that the total number of ways of ranking 10 different people is 10P10 or 10!

For X=1, the first position can be taken by any of the 5 women. The possible ways of the first person being a woman is 5C1. The rest of the 9 people can take any of the ranks. They can be ordered in 9P9 ways.

So, P(X=1) = (5C1)(9P9)/(10P10) = (5 x 362880)/(3628800) = 1/2

For X=2, the first rank must be taken by a male. The number of ways to arrange the first person as a male out of the 5 men can be calculated by 5P1. The second position must be taken by a female and rest of the 8 positions can be taken by any of the 8 people in 8P8 ways.

So, P(X=2) = (5P1)(5C1)(8P8)/(10P10) = (5 x 5 x 40320)/(3628800) = 5/18

For X=3, first two people must be men and the number of ways to arrange 2 out of 5 males at the first two positions is 5P2. The third position is a female. The rest of the 7 people can be ordered in 7P7 ways.

P(X=3) = (5P2)(5C1)(7P7)/(10P10) = (20 x 5 x 5040)/(3628800) = 5/36

P(X=4) = (5P3)(5C1)(6P6)/(10P10) = (60 x 5 x 720)/(3628800) = 5/84

P(X=5) = (5P4)(5C1)(5P5)/(10P10) = (120 x 5 x 120)/(3628800) = 5/252

P(X=6) = (5P5)(5C1)(4P4)/(10P10) = (120 x 5 x 24)/(3628800) = 1/252

P(X=7) = 0

P(X=8) = 0

P(X=9) = 0

P(X=10) = 0

7 0

3 years ago