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3 years ago

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Marty teaches music in his community. He teaches three classes a day, and each class has fewer than 8 students. If Marty teaches

x students a day, which is the simplest inequality that represents this situation?
A.
x < 16
B.
x < 24
C.
x < 8
D.
x > 24
E.
x > 8

1 answer:

Molodets [167]3 years ago

8 0

It is c becase x<8 translates to x is less than 8

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PLEASE HELP ME (will mark brainliest

jonny [76]

Answer:

The answers I got might not be right but:

47. Equation: (3x)-(7+5x)=25 x= -16

48. Equation: x÷(-3+6)=9 x=37

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3 years ago

Coach velez took the basketball team out for ice cream sundaes.He bought 8 sundaes at $5.35 each.He left a 15% tip.How much did

joja [24]

To find the value of Coach Velez's total bill, first we must figure out how much the total of all of the ice cream sundaes were.

To do this, we must multiply the number of sundaes (8) by the cost of each sundae ($5.35).

8 * 5.35 = $42.80

However, Coach Velez also left a tip of 15%. To find out how much Coach Velez tipped, we have to multiply his regular bill ($42.80) times the amount he is tipping (15% or 0.15)

$42.80 * 0.15 = $6.42

Finally, we just have to add the bill ($42.80) and the tip ($6.42) together to find Coach Velez's total amount.

$42.80 + $6.42 = $49.22

Coach Velez spent $49.22 in all.

7 0

3 years ago

Greg’s house is 0.8 miles from the library. So far, Greg has walked 5/6 of the distance. How many miles has he walked in fractio

Anastaziya [24]

Greg has walked $\frac{2}{3}$ miles

<em><u>Solution:</u></em>

Given that, Greg’s house is 0.8 miles from the library

Distance between house and library = 0.8 miles

Greg has walked $\frac{5}{6}$ of the distance

Therefore,

Distance walked = $\frac{5}{6}$ of the distance between house and library

Here "of" means multiplication

Thus we get,

$\text{Distance walked } = \frac{5}{6} \text{ of } 0.8$

$\rightarrow \frac{5}{6} \times 0.8 = \frac{5}{6} \times \frac{8}{10}\\\\\text{Simplify the above fraction by reducing to lowest terms }\\\\\rightarrow \frac{5}{6} \times \frac{8}{10}=\frac{2}{3}$

Thus Greg has walked $\frac{2}{3}$ miles

8 0

3 years ago

An object is launched from a platform. its height in meters X seconds after the launch is modeled by h(x)=-5x^2+20x+60 how m

Alex

Answer:

6 seconds after launch.

Step-by-step explanation:

You should make sure there aren't odd symbols in your question when you post it.

Assuming it is just the equation -5x^2 + 20x + 60, if you graph it you can see the path of the ball. at x=0 this is the starting point It then hits the ground when it touches the x axis. So this is finding zeroes of a quadratic.

You could do this several ways; find a way to factor it, guess and check, the quadratic formula or completing the square. I will complete the square as that is what I am most used to. If you would like to see another let me know.

The first step in completing the square is making sure the x^2 has a coefficient of 1, so now it has -5 so we have to factor out -5 from the equation.

-5x^2+20x+60 = -5(x^2 - 4x - 12)

Now you only really need to focus on the factored expression, but I will continue writing everything. The next step is to find (b/2)^2 where b is the coefficient of the x term. In this case -4. so (b/2)^2 = (-4/2)^2 = 4.

Again, focusing on x^2 - 4x - 12 you want to add and subtract (b/2)^2 from that expression. since you are adding and subtracting you are not changing the value, but we can use this.

-5(x^2 - 4x - 12) = -5(x^2 - 4x - 12 + 4 - 4)

Here you want to rearrange it a bit. Originally c was the constant term, -12, now you want it to be the positive (b/2)^2, which is positive 4. also you can combine the two other constant terms. the original c and -(b/2)^2, but I will hold off for now so I don't do too much at once.

-5(x^2 - 4x - 12 + 4 - 4) = -5(x^2 - 4x + 4 - 12 - 4)

Now you focus on x^2 - 4x + 4. Hope fully you recognize this is the same as (x-2)^2. This always happens at this step of the process. also notice -2 = b/2. Using only variables here are the first steps.

ax^2 + bx + c

a(x^2 + (b/a)x + (c/a))

a(x^2 + (b/a)x + (c/a) + (b/(2a))^2 - (b/(2a)^2)

a(x^2 + (b/a)x + (b/(2a))^2 + (c/a) - (b/(2a))^2)

a((x + b/(2a))^2 + (c/a) - (b/(2a))^2)

Again, being able to make x^2 - 4x + 4 into (x-2)^2 or x^2 + (b/a)x + (b/(2a))^2 into (x + b/(2a))^2 willa lways happen. this is because if you expand (x + b/(2a))^2 you always get x^2 + (b/a)x + (b/(2a))^2.

Now I would combine the -12-4

-5(x^2 - 4x + 4 - 12 - 4) = -5((x - 2)^2 - 12 - 4) = -5((x - 2)^2 - 16)

If you redistribute the -5 you get vertex form, but I am going to stop here because I will just undo that in the next step. So this is the form you want. Finally we can find when it equals 0. So, you set this equal to 0 and use algebra to solve.

-5((x - 2)^2 - 16) = 0

Divide both sides by -5

(x-2)^2 - 16 = 0

add 16 to both sides

(x-2)^2 = 16

Take the square root of both sides, but also count botht he positive and negative version of the answer. the reason is both 2 and -2 squared get you 4.

x - 2 = +/-4

I am using +/- to indicate I am using both positive and negative 4. Now though add 2 to both sides. since you have +/- 4 you are going to get two different results. -4+2 and 4+2

x = -2 and 6.

now, the question wants times after x=0 (the start) so you only get 6. so x=6, or in other words 6 seconds after launch.

Let me know if you have any questions.

3 0

3 years ago

Mei draws three pairs of parallel lines that are each intersected by a third line. In each figure, she measures a pair of angles

blsea [12.9K]

Consider the picture, and check the choices:

A. The alternate interior angles, are also called Z angles, because of the Z shape they create.

examples of Z angles, are the green angles and purple angles shown in the picture.

They really look identical (congruent)

B.

No: check the green angles in figure 1, and purple angles if figure 2. they are not acute.

C.

No. In each case, we have the same number of acute angles and obtuse angles,

except case3, where the intersecting line, is perpendicular to the parallel lines.

D.
No, by the same reasoning used in part C. Only when the intersecting line cuts the 2 parallel lines perpendicularly, all the angles are congruent.

Answer: A

4 0

3 years ago