Hello from MrBillDoesMath!
Answer:
b = 0.6
Discussion:
The question can be written as
b - 7.4 = -6.8 => (now add 7.4 to each side)
b - 7.4 + 7.4 = -6.8 + 7.4 => ( note: -7.4 + 7.4 = 0)
b = 0.6
Thank you,
MrB
A]
D=R×t
d=5.8r
d2=5.1(r+7)
0.7r=35.7
r=51 mi/hr
thus the average speed on the outbound trip would be:
51+7=58 mi/hr
b]
let speed of fishing boat=x km/h
speed of cruise ship=(x+12.5) km/h
distance traveled by fishing boat=11.5×x=11.5x km
distance traveled by cruise ship=(x+12.5)×11=(11x+137.5) km
Total distance covered by the ships:
11.5x+11x+137.5=322
22.5x=322-137.5
22.5x=184.5
thus
x=184.5/22.5
x=8.2 km/h
The speed of fishing boat is 8.2 km/hr
Answer:
12.5663706144
If necessary, and if your system/teacher allows it, just keep it down to 1-3 decimals.
Hope I could help! :D
Answer:
A = 1, B = 0, C = 7
Step-by-step explanation:
The egg follows the path x = 7, so the equation is ...
1x +0y = 7
A = 1, B = 0, C = 7
Answer:
20.2 miles
Step-by-step explanation:
This can be described by the three sides of a right angled triangle. Let the distance of the glider to the airport be represented by x, applying the Pythagoras theorem:
= 
+ 
= 
+ 
576 = 
+ 169
= 576 - 169
= 407
x = 
= 20.1742
x = 20.2 miles
The glider has to fly 20.2 miles to return to the airport.
