What is the formula to find the area of parallelogram

Evaluate 3x^2 - x for x = -2

Butoxors [25]

Answer:

$3x^2 - x$

$3 \times - 2 \times - 2 - 2$

$(3 \times - 2 \times - 2) - ( - 2)$

$12 + 2 = 14$

4 0

2 years ago

PLEASE HELP WHAT ARE THE coordinates for the center of the hyperbola??

solong [7]

Answer:

The coordinates of the center of the hyperbola are (1,-3)

Step-by-step explanation:

Equation of a hyperbola:

The equation of a hyperbola with center $(x_0,y_0)$ is given by:

$\frac{(x - x_0)^2}{a^2} - \frac{(y - y_0)^2}{b^2} = 1$

In this question, we have that:

$-x_0 = -1 \rightarrow x_0 = 1$

$-y_0 = 3 \rightarrow y_0 = -3$

The coordinates of the center of the hyperbola are (1,-3)

3 0

3 years ago

Ellie’s bird feeder is shaped like a cone with a height of 24 in. and a radius of 3 in. Packages of bird seed are cylindrical an

love history [14]

The volume of seeds in the package must be equal to the volume of the feeder in order to fill it completely. The volume of the conic feeder is given by:
V(f) = (πr²h)/3
And volume of the cylindrical package is given by:
V(p) = πr²h
Equating the two and substituting values:
(π x 3² x 24)/3 = π x 6² x h
h = 2 inches

3 0

3 years ago

Write an equation with a slope of -1/2 in each form. point-slope form slope-intercept form.

Evgen [1.6K]

For the case of a line through

(

2

,

7

)

and

(

1

,

−

4

)

we have

slope

m

=

Δ

y

Δ

x

=

−

4

−

7

1

−

2

=

−

11

−

1

=

11

Using the point

(

2

,

7

)

we can write the equation of the line in point slope form as:

y

−

7

=

m

(

x

−

2

)

where the slope

m

=

11

.

That is:

y

−

7

=

11

(

x

−

2

)

To get point intercept form, first expand the right hand side so...

y

−

7

=

11

x

−

(

11

⋅

2

)

=

11

x

−

22

Then add

7

to both sides to get:

y

=

11

x

−

15

=

11

x

+

(

−

15

)

This is point intercept (

y

=

m

x

+

c

) form with slope

m

=

11

and intercept

c

=

−

15

.

6 0

3 years ago

The center of a circle lies on the line y = 4x + 1 and is tangent to the x-axis at (−3,0) . What is the equation of the circle i

Hunter-Best [27]

Answer:

$(x+3)^2+(y+11)^2=121$

Step-by-step explanation:

Consider a sketch of the problem as shown in the picture, where:

Blue line is given by y = 4x + 1.
Point B is the center of the circle.
Point A is (-3, 0).

Since the center of the circle lies on the line y = 4x +1 and is tangent to the x-axis at point A, then its radius BA is perpendicular to the x-axis. To find the coordinates of point B, we must replace x = -3 into the blue line equation: y = 4x(-3) + 1 = -11.

So, we know that the center of the circle is at B=(-3, -11). And furthermore, the radius BA is of length r=11.

Since the general equation of the circle of radius lenght r centered at (h, k) is given by

$(x-h)^2+(y-k)^2=r^2$

then with h = -3, k = -11 and r= 11, the equation of our circle is

$(x+3)^2+(y+11)^2=121$

5 0

3 years ago