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2 years ago

What is the formula to find the area of parallelogram

Mathematics

2 answers:

raketka [301]2 years ago

6 0

Step-by-step explanation:

area of parallelogram= height * length of base

Fudgin [204]2 years ago

3 0

A=bh will be ur answer

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Elect two ratios that are equivalent to 6 : 10

Vika [28.1K]

Answer is :
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3 years ago

How do you solve this question

Wewaii [24]

<h2>Solution:.</h2>

Let the ceilings be a & b

and the distance from one corner of the ceiling to the opposite be c

then using Pythagoras theorem

$c = \sqrt{a {}^{2} + b {}^{2} } \\ c = \sqrt{16 {}^{2} + 12 {}^{2} } \\ c = \sqrt{256 + 144 } \\ c = \sqrt{400} \\ c = 20$

hence ,c .°. the distance from one corner of the ceiling to the opposite is 20

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2 years ago

Deserts advance linearly, in easily mappable patterns. True False

mario62 [17]

It is false that deserts advance linearly, in easily mappable patterns.
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3 years ago

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Question regarding logarithms.

Eddi Din [679]

$5^{x-2}-7^{x-3}=7^{x-5}+11\cdot5^{x-4}\\\\5^{x-2}-7^{x-2-1}=7^{x-2-3}+11\cdot5^{x-2-2}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\5^{x-2}-\dfrac{7^{x-2}}{7^1}=\dfrac{7^{x-2}}{7^3}+11\cdot\dfrac{5^{x-2}}{5^2}\\\\5^{x-2}-\dfrac{1}{7}\cdot7^{x-2}=\dfrac{1}{343}\cdot7^{x-2}+\dfrac{11}{25}\cdot5^{x-2}\\\\-\dfrac{1}{7}\cdot7^{x-2}-\dfrac{1}{343}\cdot7^{x-2}=\dfrac{11}{25}\cdot5^{x-2}-5^{x-2}\\\\\left(-\dfrac{1}{7}-\dfrac{1}{343}\right)\cdot7^{x-2}=\left(\dfrac{11}{25}-1\right)\cdot5^{x-2}$

$\left(-\dfrac{49}{343}-\dfrac{1}{343}\right)\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\\\\-\dfrac{50}{343}\cdot7^{x-2}=-\dfrac{14}{25}\cdot5^{x-2}\qquad\text{multiply both sides by}\ \left(-\dfrac{25}{14}\right)\\\\\dfrac{50\cdot25}{343\cdot14}\cdot7^{x-2}=5^{x-2}\qquad\text{divide both sides by}\ 7^{x-2}\\\\\dfrac{25\cdot25}{343\cdot7}=\dfrac{5^{x-2}}{7^{x-2}}\qquad\text{use}\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}$

$\dfrac{5^2\cdot5^2}{7^3\cdot7}=\left(\dfrac{5}{7}\right)^{x-2}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\\dfrac{5^4}{7^4}=\left(\dfrac{5}{7}\right)^{x-2}\\\\\left(\dfrac{5}{7}\right)^4=\left(\dfrac{5}{7}\right)^{x-2}\iff x-2=4\qquad\text{add 2 to both sides}\\\\\boxed{x=6}$

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3 years ago

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Write y=2x+3 using function notation

Travka [436]

F(x)=2x+3. easy as that, just replace y with f(x)

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3 years ago

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