<h2>T
he small mass should be placed at x = 11.72 cm or x = 68.28 cm </h2>
Step-by-step explanation:
Let the small mass be m and position on x axis be y.
A 20 kg sphere is at the origin.
Distance to 20 kg mass = y
A 10 kg sphere is at x = 20 cm
Distance to 10 kg sphere = 20 - y
We have forces between them are equal
We have gravitational force
Where G = 6.67 x 10⁻¹¹ N m²/kg²
M = Mass of body 1
M = Mass of body 2
r = Distance between them
Here we have
So the small mass should be placed at x = 11.72 cm or x = 68.28 cm
Answer:
20.7 miles
Step-by-step explanation:
Hope this helps!
Answer:
Most: Black 5/6
Least: Red 1/8
Step-by-step explanation:
this is the fraction, least to greatest:
1/8 < 1/4 < 2/5 < 1/2 < 7/12< 5/6
Answer:
the answer is that
Step-by-step explanation:
because i know
Answer:
h(n) = -2n -13
Step-by-step explanation:
m+1 = -2(n+6)
Distribute
m+1 = -2n-12
We want to solve for m, as we want a function of n
m +1-1 = -2n-12-1
m = -2n-13
h(n) = -2n -13