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WINSTONCH [101]
4 years ago
12

Jarvis works in a garage £6 an hour. If he works on Saturday, he is paid time and a quarter. If he works on Sunday, he is paid t

ime and a half Last weekend Jarvis worked for six hours on Saturday and five hours on Sunday. How much more Jarvis paid last weekend altogether?
Mathematics
1 answer:
ruslelena [56]4 years ago
4 0

Answer: He is paid $90 last weekend.

Step-by-step explanation:

Since we have given that

Amount he earns per hour = $6

If he works on Saturday, he is paid time and a quarter .

Amount would be

6\times 1.25=\$7.5

If he works on Sunday, he is paid time and a half.

Amount would be

6\times 1.5=\$9

Number of hours he worked on Saturday = 6 hours

Number of hours he worked on Sunday = 5 hours

So, Total amount he is paid last weekend altogether is given by

6\times 7.5+5\times 9\\\\=\$90

Hence, he is paid $90 last weekend.

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You have a Rectangle with sides of 5ft and 8ft; solve for its perimeter and area.
Nezavi [6.7K]

Answer:

Perimeter = 2(l+w) = 2*(5+8) = 26ft

Area = wl = 8*5 = 40

Step-by-step explanation:

pretty sure :)

6 0
2 years ago
32x+5 = 3x - 3<br> Solving exponential equations
Likurg_2 [28]

Answer:

x = -8/29 = -0.276

Step-by-step explanation:

Step  1  :

Solving a Single Variable Equation :

1.1      Solve  :    29x+8 = 0

Subtract  8  from both sides of the equation :

                     29x = -8

Divide both sides of the equation by 29:

                    x = -8/29 = -0.276

One solution was found :

                  x = -8/29 = -0.276

Processing ends successfully

plz mark me as brainliest :)

5 0
3 years ago
Read 2 more answers
Simplify 3a + 4b + 5c + (-2a) + b
ad-work [718]

Answer:

<em> </em><em>a </em><em>+</em><em> </em><em>5</em><em>b</em><em> </em><em>+</em><em> </em><em>5</em><em>c</em>

Step-by-step explanation:

here's your solution

=> 3a + 4b + 5c +(-2a) + b

=> solve for like term

=> 3a - 2a + 4b + b + 5c

=> a + 5b + 5c

hope it helps

7 0
3 years ago
Read 2 more answers
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks along the x-axis from the spotlight toward the bui
Sedbober [7]

Answer:

0.675 m/s

Step-by-step explanation:

Let height of shadow= y,CD=x

Height of man=2 m

Speed of man= \frac{dx}{dt}=1. 8 m/s

\triangle ABD\sim\triangle ECD

Therefore, \frac{AB}{EC}=\frac{BD}{CD}

\frac{y}{2}=\frac{12}{x}

xy=24

Differentiate w.r.t t

x\frac{dy}{dt}+y\frac{dx}{dt}=0

x\frac{dy}{dt}=-y\frac{dx}{dt}

\frac{dy}{dt}=-\frac{y}{x}\frac{dx}{dt}

When the man is 4 m from  the building

Then, we have x=12-4=8 m

\frac{dx}{dt}=1.8 m/s

Substitute the values in above equation then, we get

8y=24

y=\frac{24}{8}=3

Substitute the values then we get

\frac{dy}{dt}=-\frac{3}{8}\times 1.8=-0.675 m/s

Hence, the length of his shadow on the building decreasing at the rate 0.675 m/s.

8 0
3 years ago
Pleaseee help !! I’ll give brainliest !
Luda [366]

Answer: 8 in

Step-by-step explanation:

mAB= 8 inches because AB is the difference of AD and BD. The postulate I used for this is the Part Whole Postulate, or PWP.

8 0
3 years ago
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