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Flura [38]
3 years ago
12

Identifying an Error

Mathematics
1 answer:
PtichkaEL [24]3 years ago
4 0
The answer should be A because when you multiply two negatives it comes out positive
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Which transformations are needed to change the parent cosine function to y = 3 cosine (10 (x minus pi))?
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Answer:

See Explanation

Step-by-step explanation:

Given

New function: y = 3 \cos(10 (x -\pi))

We can assume the parent function to be:

y = \cos (x)

The new function can be represented as:

y = A*\cos((\frac{2\pi}{B})(x-c))

Where

A = Vertical stretch factor

B = Period

C = Right shift

By comparison:

y = A*\cos((\frac{2\pi}{B})(x-c)) to y = 3 \cos(10 (x -\pi))

A = 3

c = \pi

\frac{2\pi}{B} = 10

Solve for B

B = \frac{2\pi}{10}

B = \frac{\pi}{5}

Using the calculated values of A,\ B\ and\ c. This implies that, the following transformations occur on the parent function:

  • <em>Vertically stretched by </em>3<em />
  • <em>Horizontally compressed by </em>\frac{\pi}{5}<em />
  • <em>Right shifted by </em>\pi<em />
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