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3 years ago

Who was the first person to find out pi (3.14)

1 answer:

3 0

The first person who calculated pi was Archimedes got really close however with the mathematics he had in his time he did not have decimal points nor could he use the number 0. So it has to latter once people recognize 0 as a number and the decimal point that we get what we have today.

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A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student

yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - α)% confidence interval for the difference between population means is:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

The information provided is as follows:

$n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43$

The critical value of z for 98% confidence level is,

$z_{\alpha/2}=z_{0.02/2}=2.326$

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

$CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}$

$=(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)$

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

5 0

3 years ago

CAN YOU HELP ME PLEASE

mamaluj [8]

Answer:

Step-by-step explanation:

7 0

3 years ago

Please answer hurry!!!!

lutik1710 [3]

The best way to solve this problem is by plugging in each answer choice for both equations and seeing which one works. You can already see that choice A doesn't work because -1 is not greater than or equal to 4. That means you just need to test choices B and C!

Choice B (4, -2)
$x + y \geq 6\\
4 + -2 \geq 6\\
2 \geq 6 
$
2 is not greater than or equal to 6, so choice B doesn't work.

Choice C (4, 2)
$x + y \geq 6\\ 
4 + 2 \geq 6\\ 
6 \geq 6 \\\\
x \geq 4\\
4 \geq 4$
Since 6 is equal to 6 and 4 is equal to 4, choice C works!

-------

Answer: C) (4, 2)

6 0

2 years ago

Can someone please help me with question 4

bazaltina [42]

Yes what is the four question

4 0

3 years ago

Solve the system of equations using the substitution method.

andre [41]

Answer: (-0.0549,-1.0732)

8 0

3 years ago

Read 2 more answers