Answer:
what are you doing here honey and what is this gonna be about me in a hurry for the first two
1) in order to solve this problem you must to obtain The value of K, for it you know by definition that the horizontal slope of the side BC is zero ,
then m = Y2-Y/X2-X1, 0 = 5-K/4-6⇒0 = 5-K⇒K = 5
known this value for K you ca find the equation of thE line that pass through A and C
2) Following the same procedure in first place you calculate the slope with the points A(-2,1) Y C ( 4,5)
m= 5-1/4-(-2) = 2
now with any point A or C and the slope you obtain the line
A(-2,1)
y-y1 = m (x-x1) , Y-1= 2(X-(-2)⇒Y-1= 2X+4⇒Y=2X+4-1⇒Y =2X+3
Answer:
Because if it is zero, then it is multiplied the variable and it will be zero. For example if I had 0x(squared) + x, it would just be x because zero times any number is zero. Looking at the problem, I would assume it was quadratic because it had x squared, but it isn't because there are 0 x squared values.
Step-by-step explanation:
Choice B because when you use distributive property, you'll get 3x+3x+3y*3x+3x+3y
