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enot [183]
2 years ago
15

Increase the number 1.25 by 8/25 of it

Mathematics
1 answer:
jolli1 [7]2 years ago
5 0

Answer: 1.65

Step-by-step explanation:

     First, we must find 8/25 of 1.25. This is using multiplication.

1.25 * 8/25 = 0.4

    Now, we can increase 1.25 by 8/25 of it. This is using addition.

1.25 + 0.4 = 1.65

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the congruent sides of an isosceles triangle are each 1 unit longer than the length of the shortest side of the triangle. the pe
igor_vitrenko [27]
Let x units be the length of the shortest side of the triangle.
Perimeter of triangle = 2(x + 1) +x = 3x + 2
Perimeter of square = 4(x - 2) = 4x - 8
Equating the two expressions for perimeters, we get:
3x + 2 = 4x - 8
The solution is: x = 10

The answer is 10 units.
6 0
3 years ago
Read 2 more answers
Please please help me out!!!!!
Sliva [168]

Answer:

The answer to your question is: g(3) = 34

Step-by-step explanation:

Function                   g(x) = 4(x)² - 3(x) + 7

                                 g(3) = 4(3)² - 3(3) + 7               substitution

                                 g(3) = 4(9) - 3(3) + 7                 simplify

                                 g(3) = 36 - 9 + 7

                                 g(3) = 36 - 2

                                  g(3) = 34

                               

7 0
4 years ago
The ratio of the sides of 2 cubes is 2 to 7. If the volume of the smaller cube is 32 u3, then the volume of the larger cube is _
satela [25.4K]
\bf \qquad \qquad \textit{ratio relations}
\\\\
\begin{array}{ccccllll}
&Sides&Area&Volume\\
&-----&-----&-----\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}&\cfrac{s}{s}&\cfrac{s^2}{s^2}&\cfrac{s^3}{s^3}
\end{array} \\\\
-----------------------------\\\\
\cfrac{\textit{similar shape}}{\textit{similar shape}}\qquad \cfrac{s}{s}=\cfrac{\sqrt{s^2}}{\sqrt{s^2}}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\\\\
-------------------------------\\\\

\bf \cfrac{small}{large}\qquad \cfrac{s}{s}=\cfrac{\sqrt[3]{s^3}}{\sqrt[3]{s^3}}\implies \cfrac{2}{7}=\cfrac{\sqrt[3]{32}}{\sqrt[3]{v}}\implies \cfrac{2}{7}=\sqrt[3]{\cfrac{32}{v}}\implies \left( \cfrac{2}{7} \right)^3=\cfrac{32}{v}
\\\\\\
\cfrac{2^3}{7^3}=\cfrac{32}{v}\implies v=\cfrac{7^3\cdot 32}{2^3}
5 0
3 years ago
Find the area of the figure. Use 3.14 for π.
siniylev [52]

Answer:

Area of the figure= 51.5feet^2

Step-by-step explanation:

Area of the figure=Area of the middle rectangle+ Area the the two triangles

Area of the rectangle=Length*Width

Length= 8+3 =11 feet\\\\Width=4 feet

Area = 11*4\\\\      =44 feet^2

Area of the triangle with the height of 2 feet and base= 3 feet

Area= \frac{1}{2} *Base*Height

==\frac{1}{2} *3*2\\\\=\frac{1}{2}*6\\\\ =3 feet^2

Area of the triangle with the Height=3 feet and Base= 3 feet

Area= \frac{1}{2} *Base*Height

=\frac{1}{2}*3*3\\\\ =\frac{1}{2}*9\\\\ =4.5feet^2

Total Area of the figure=44+3+4.5=51.5 feet^2

5 0
3 years ago
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Which quadrant in a coordinate plane has two positive points
vodomira [7]

Answer:

The first quadrant

Step-by-step explanation:

Aka upper right quadrant

6 0
3 years ago
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