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Rasek [7]
3 years ago
7

Write the number 0.00003489 in the form a x 10k

Mathematics
2 answers:
Firlakuza [10]3 years ago
6 0

Answer:

3.489 * 10^-5

Step-by-step explanation:

hoa [83]3 years ago
4 0

Answer:

that is wrong you know, right?

Step-by-step explanation:

You might be interested in
7(4x - 2) - 4(2x - 8)
vesna_86 [32]

Answer:

20x + 18

Step-by-step explanation:

We need to use the distributive property, where we essentially take the sum of the product of the outside number with each of the inside terms.

In 7(4x - 2), 7 is the outside number and 4x and -2 are the inside numbers, so:

7(4x - 2) = 7 * 4x + 7 * (-2) = 28x - 14

In 4(2x - 8), 4 is the outside number and 2x and -8 are the inside numbers, so:

4(2x - 8) = 4 * 2x + 4 * (-8) = 8x - 32

Now, we have:

28x - 14 - (8x - 32) = 28x - 14 - 8x + 32 = 20x + 18

The answer is 20x + 18.

6 0
3 years ago
Read 2 more answers
Warm-Up
Serjik [45]

Answer:

using the formula

we replace the coordinates

the we calculate

the answer will be square 100 which will give us 10

5 0
3 years ago
*!HELP!* Mark wants to order a pizza. Drag and drop the correct number or phrase into each box to complete the explanation for w
fredd [130]

Answer:

A. 0.08 B. 0.09 and C. 12-inch hopefully im right

8 0
2 years ago
Please help me solve!
Elina [12.6K]

Answer:

Step-by-step explanation:

Comment

There are a number of ways of doing this problem. I don't know which method you are intended to use. One sure way in this case is graphing the equation, I have done this for you. See below. The maximum volume occurs where x = 2

The graph shows that there is a peak at x = 2. That is where the maximum volume is,

Answer

x = 2

6 0
2 years ago
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
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